Find a particular solution yp of the following equation using the Method of Undetermined Coefficients. Primes denote the derivatives with respect to t. y" +5y' +10y=510 e²t cos 6t

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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### Finding a Particular Solution using the Method of Undetermined Coefficients

**Objective**: Find a particular solution \( y_p \) of the following differential equation using the Method of Undetermined Coefficients. In this context, primes denote the derivatives with respect to \( t \).

#### Equation:
\[ y'' + 5y' + 10y = 510 e^{2t} \cos 6t \]

---

**Solution**: A particular solution is \( y_p(t) = \) [input box for user to enter the function].

In the differential equation given above:
- \( y'' \) is the second derivative of \( y \) with respect to \( t \),
- \( y' \) is the first derivative of \( y \) with respect to \( t \),
- The right-hand side of the equation contains \( 510 e^{2t} \cos 6t \), which indicates the form of the non-homogeneous term that needs to be used when assuming a particular solution using the Method of Undetermined Coefficients.

---

To solve this, one should typically assume a particular solution of a similar form to the non-homogeneous term. Given the non-homogeneous term includes \( e^{2t} \cos 6t \), the assumed form for \( y_p \) could be:

\[ y_p(t) = (Ae^{2t}\cos 6t + Be^{2t}\sin 6t) \]

Where \( A \) and \( B \) are constants to be determined.

By substituting this assumed solution back into the differential equation and solving for the coefficients, one can determine the values of \( A \) and \( B \).

Finally, substitute the calculated values back into the assumed form to get the particular solution \( y_p(t) \).
Transcribed Image Text:### Finding a Particular Solution using the Method of Undetermined Coefficients **Objective**: Find a particular solution \( y_p \) of the following differential equation using the Method of Undetermined Coefficients. In this context, primes denote the derivatives with respect to \( t \). #### Equation: \[ y'' + 5y' + 10y = 510 e^{2t} \cos 6t \] --- **Solution**: A particular solution is \( y_p(t) = \) [input box for user to enter the function]. In the differential equation given above: - \( y'' \) is the second derivative of \( y \) with respect to \( t \), - \( y' \) is the first derivative of \( y \) with respect to \( t \), - The right-hand side of the equation contains \( 510 e^{2t} \cos 6t \), which indicates the form of the non-homogeneous term that needs to be used when assuming a particular solution using the Method of Undetermined Coefficients. --- To solve this, one should typically assume a particular solution of a similar form to the non-homogeneous term. Given the non-homogeneous term includes \( e^{2t} \cos 6t \), the assumed form for \( y_p \) could be: \[ y_p(t) = (Ae^{2t}\cos 6t + Be^{2t}\sin 6t) \] Where \( A \) and \( B \) are constants to be determined. By substituting this assumed solution back into the differential equation and solving for the coefficients, one can determine the values of \( A \) and \( B \). Finally, substitute the calculated values back into the assumed form to get the particular solution \( y_p(t) \).
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