Nn.70.Subject :- Advance Mathematic Find a particular solution of the indicated linear system that satisfies the initial conditions x₁ (0) = 12, x₂ (0) = 0.4e6tPICHAX; X₁7e6tX' =13 428-10=The particular solution is x₁ (t) =e-3t4e-3t=and x₂ (t) = .

(.) Given system is , x' = 13-428-10x and x1=4e6t7e6t , x2=e-3t4e-3t The…

Answered: Find a particular solution of the…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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An environmental engineer wants to evaluate three different methods for disposing of nonhazardous chemical waste: land application, fluidized-bed incineration, and private disposal contract. Use the estimates below to help her determine which has the least cost at /= 15.00% per year on the basis of an annual worth evaluation. First Cost AOC per Year Salvage Value Life Land $-145000 $-86000 $23000 4 years Incineration $-760000 $-70000 $260000 6 years Contract O $-132000 O 2 years
O0 * 41) 57% ID X A ixl.com/math/grade-6/identify-mistakes-involving-the-order-of-operations Joey tried to evaluate an expression. Here is his work: 97 - 3 + 5° ÷ 25 · 2.3? = 97 3 + 125 ÷ 25 · 2.9 Step 1 = 97 – 3 + 5 2.9 Step 2 = 97 - 3 + 10-9 Step 3 = 97 3 +90 Step 4 = 97 - 93 Step 5 = 4 Step 6 Is Joey's work correct? No, Joey made a mistake going from the given expression to Step 1. Joey should have multiplied 2 and 3 instead of evaluating exponents. The order of operations says to multiply before you evaluate exponents. No, Joey made a mistake going from Step 4 to Step 5. Joey should have subtracted 3 from 97 before adding. The order of operations says to add and subtract from left to right. Yes, Joey's work is correct. MacBook Pro 日

Please do the following questions with handwritten working out The answer is in the other image
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Find a particular solution of the indicated linear system that satisfies the initial conditions x₁ (0) = 12, x₂ (0) = 0. RICHA 4e6t X; X₁ = 7e6t X' = 13 -4 28-10 = e-3t 4e-3t The particular solution is x₁ (t) = and x₂ (t) = .