Find a limit equal to (x2 – 8)dx. 3

Q: Find ∫√(2x − 1) dx.

A: Given:

Q: Differentiate. y= In [(x +2)° (x + 5 (x+ 7)°] [In [x+ 2)° (x +5)*(x + 7) ]] =O dx

A:

Q: Find the cost function for the marginal cost function. 0.02x. C'(x) = 0.07 e fixed cost is $5 C(x) =

A: To solve the integral

Q: (I+x²)d (l-x²) Vi+

A:

Q: (3-5x) 2. (3- 1y(r – 1) d (3х - 1) (х —1)2

A:

Q: Determine the following: L (x - 2x2 + 1/3x) dx

A:

Q: (2x³-9x²+2) dx from x = 6 to x = 11

A: Given: ∫2x3-9x2+2dx   from x=6 to x=11

Q: | 1/(x3 – 8) dx

A: To evaluate: I=∫1x3-8dx  I=∫1x3-23dx We know that x3-a3=x-ax2+ax+a2 ⇒I=∫1x-2x2+2x+4dx

Q: Find ∫sec2 (5x + 1). 5 dx.

A: we have to find the value of the given indefinite integral. ∫sec25x+1·5dx

Q: Find ∫ dx/√(e2x − 1)

A:

Q: .2 dx Jo (9 + x²)2

A:

Q: .2 dx 6. (x-1)3

A:

Q: X arccsc(x- + 13) dx 6. 10

A:

Q: dy Find for y = x(4x + 3) dx - |3

A: The function is given by y = x4x+313 To evaluate : dydx

Q: Evaluate.

A:

Q: Evaluate x(x2 + 1)3 dx.

A: Given ∫x(x2+1)3dx

Q: 1. [²+3x - 4)dx

A:

Q: Find. (x²+1)3 2x dx

A:

Q: al3x cosec/3 Evaluate |sec*x cosec x dx.

A:

Q: 3. Find [(5-x² +18) dx

A: Find     ∫5-x2+18x4dx

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.