Hello . I have attached a problem . please address it. Tnx. Do it for a: 00 b: 01 c:11Thanks in advance **Transcription and Explanation for Educational Website**---**Problem Statement:**Find a JK-FF (JK Flip-Flop) implementation of a 1-input (x), 1-output (z) clocked sequential circuit defined by the following state diagram.**State Diagram Description:**The diagram consists of two states and transitions represented as follows:- There are two states, labeled `0` and `1`.- **State `0`:** - The output (z) is 0. - From state `0`, if the input (x) is 0, the system transitions to state `0`. - From state `0`, if the input (x) is 1, the system transitions to state `1`.- **State `1`:** - The output (z) is 1. - From state `1`, if the input (x) is 0, the system transitions to state `0`. - From state `1`, if the input (x) is 1, the system remains in state `1`.**Note:**This is a Moore-type circuit, where the output is determined solely by the current state, not by the input.**Requirements for Solution:**Your answer must include the following components:1. **State Table:** A detailed table that lists the states, inputs, next states, and outputs.2. **State Assignment:** Assign binary codes to the states for simplification.3. **Transition Table:** A table indicating state transitions based on inputs.4. **Excitation Table:** A table to determine JK flip-flop inputs necessary to achieve the desired state transitions.5. **Excitation Karnaugh Maps:** Use Karnaugh maps to simplify the logic expressions for JK inputs.6. **Logic Circuit Diagram:** The complete logical circuit implementation using JK flip-flops.---This transcription explains the task details, defines the components to be produced, and provides insights into the state diagram and its expected analysis.

According to the question, for the given state diagram as shown below We need to design the logic circuit by using JK flip flop.State table: As the given data, a=00, b=01; State assignment table: Transition table: Input Present state Next state Output 0 00 00 0 1 00 01 1 0 01 00 0 1 01 01 1Excitation table: Since there are two states, hence two JK flip flops are used. Present state Input (X) Next state J1 K1 J0 K0 Output (Z) 00 0 00 0 X 0 X 0 00 1 01 0 X 1 X 1 01 0 00 0 X X 1 0 01 1 01 0 X X 0 1 10 0 XX X X X X X 10 1 XX X X X X X 11 0 XX X X X X X 11 1 XX X X X X X K-Map: K-map for J1: J1=0 K-map for K1: K1=0 OR 1:K-Map for J0: J0=X.Q0 : K-Map for K0: K0=X K-Map for output (Z): Z=XCircuit diagram: