Find a general solution to the given differential equation. y'' + 7y' - 18y=0 A general solution is y(t) = C₁ e 2t + C₂ e - 9t

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Solving Differential Equations**

**Objective:**
Find a general solution to the given differential equation.

**Equation:**
\[ y'' + 7y' - 18y = 0 \]

**General Solution:**
A general solution to the given differential equation is:
\[ y(t) = c_1 e^{2t} + c_2 e^{-9t} \]

Where:
- \( c_1 \) and \( c_2 \) are arbitrary constants.
- \( e \) represents the base of the natural logarithm.
- \( t \) is the independent variable (often representing time).

**Description:**
This solution involves finding the characteristic equation of the differential equation and solving for its roots. The exponential terms \( e^{2t} \) and \( e^{-9t} \) are derived from these roots, and they form the basis of the general solution combined with arbitrary constants.
Transcribed Image Text:**Solving Differential Equations** **Objective:** Find a general solution to the given differential equation. **Equation:** \[ y'' + 7y' - 18y = 0 \] **General Solution:** A general solution to the given differential equation is: \[ y(t) = c_1 e^{2t} + c_2 e^{-9t} \] Where: - \( c_1 \) and \( c_2 \) are arbitrary constants. - \( e \) represents the base of the natural logarithm. - \( t \) is the independent variable (often representing time). **Description:** This solution involves finding the characteristic equation of the differential equation and solving for its roots. The exponential terms \( e^{2t} \) and \( e^{-9t} \) are derived from these roots, and they form the basis of the general solution combined with arbitrary constants.
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