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Find a general solution to each linear ODE, and then find the specific solution with the given initial condition by using the integrating factor (a) u' (t) = u(t)+3, u(0) = 3 (b) u' (t) = 2u(t) + 4, u(0) = 0 (c) u' (t) = −3u(t) +3, u(0) = 5 (d) u' (t) = −3u(t) +9t, u(0) = 5

Find a general solution to each linear ODE, and then find the specific solution with the given initial condition by using the integrating factor (a) u' (t) = u(t)+3, u(0) = 3 (b) u' (t) = 2u(t) + 4, u(0) = 0 (c) u' (t) = −3u(t) +3, u(0) = 5 (d) u' (t) = −3u(t) +9t, u(0) = 5

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Find a general solution to each linear ODE, and then find the specific solution with the given initial condition by using the integrating factor (a) u'(t) = u(t)+3, u(0) = 3 (b) u'(t) = 2u(t)+4, u(0) = 0 (c) u'(t) = −3u(t) +3, u(0) = 5 (d) u'(t) = −3u(t) +9t, u(0) = 5 (e) u' (t) = u(t)+2sin(t), u(0) = 1 (f) u'(t) = −4u(t) + e¹, u(0) = 2 (g) u'(t)= tu(t)+t, u(0) = 2 (h) u' (t) = u(t)/t+2, u(1) = 3 (i) u' (t) = sin(t)u(t) + sin(t), u(0) = 4 (j) u' (t) = au(t) +b, u(0) = uo, where a, b, and uo are constants
Transcribed Image Text:Find a general solution to each linear ODE, and then find the specific solution with the given initial condition by using the integrating factor (a) u'(t) = u(t)+3, u(0) = 3 (b) u'(t) = 2u(t)+4, u(0) = 0 (c) u'(t) = −3u(t) +3, u(0) = 5 (d) u'(t) = −3u(t) +9t, u(0) = 5 (e) u' (t) = u(t)+2sin(t), u(0) = 1 (f) u'(t) = −4u(t) + e¹, u(0) = 2 (g) u'(t)= tu(t)+t, u(0) = 2 (h) u' (t) = u(t)/t+2, u(1) = 3 (i) u' (t) = sin(t)u(t) + sin(t), u(0) = 4 (j) u' (t) = au(t) +b, u(0) = uo, where a, b, and uo are constants
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