Find a basis for the null space of the linear transformation T: R4 →→ R³ and state the nullity. x1 3x2 + 5x3+15x4 3x₁8x22x3 - 23x4 4x1+7x2 + x3 16x4 T(x) = Enter vectors horizontally surrounded by [ and ] where elements are separated by commas. The nullity is 3 - X

Q: #1 only

A: Amarjeet 2mr find x.

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Q: 2x be17eX +l2=O

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Q: a3-16a

A: a³−16a ⇒a(a²−16) ⇒a(a² −4²) ⇒a(a+4)(a−4)

Q: A-1 does not exist.

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Q: Find X ,Y and Z

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Q: Multiply. 3 x-4 3 3 2 X+4

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Q: Express the graph in Figure Q3(a) in terms of a unit step function and then find the Laplace…

A: We have to find the Laplace transform of given graph in term of unit step function

Q: 3. Identify all the cycles at each node of the directed graph above.

A: Cycle is defined as a path that start and end at the same vertex.

Q: Add. 4 4a + 3

A: Here given

Q: 2n aO 1p0 .b TT 2 IT.dO

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Q: i 15Y4 + 32X+ 23x?+ 25X-3

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Q: Part 1,2,3

A: The point is, 6,-2 So, the point is in 4th quadrant.

Q: xy dxdy Hw

A: See attached file for a step by step explanation.

Q: Find A

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Q: 42 -13

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Q: L'im 2x - 3

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Q: y et 2x *Sec2X Pinel dy o

A: By using these differential formulas that are ddxex=ex, ddxax=axlnx where a is constant,…

Q: and

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Q: (25 dx +3x

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Q: A= A

A: We will find out the required value.

Q: 1 3 8.

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Q: Simplify. -4x + 4x | -2x 是A 3. -4x +4x 2. 3 2. X -2x

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