Find (4x + 2y)dA where R is the parallelogram with vertices (0,0), (1,2), (5,4), and (6,6). R Use the transformation x = u +5v, y = 2u +4v

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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### Problem Statement

Find the double integral:

\[ \iint_R (4x + 2y) \, dA \]

where \( R \) is the parallelogram with vertices at \( (0,0) \), \( (1,2) \), \( (5,4) \), and \( (6,6) \).

Use the transformation:

\[ x = u + 5v, \quad y = 2u + 4v \]

---

#### Explanation:

This problem requires evaluating a double integral over a given region \( R \), which in this case is a parallelogram. 

The vertices of the parallelogram are:
- \( (0,0) \)
- \( (1,2) \)
- \( (5,4) \)
- \( (6,6) \)

A linear transformation is provided to simplify the region over which the integral is taken:

\[ x = u + 5v \]
\[ y = 2u + 4v \]

Using this transformation, the problem asks to compute the integral in the new coordinates. The function to be integrated is \( 4x + 2y \).
Transcribed Image Text:### Problem Statement Find the double integral: \[ \iint_R (4x + 2y) \, dA \] where \( R \) is the parallelogram with vertices at \( (0,0) \), \( (1,2) \), \( (5,4) \), and \( (6,6) \). Use the transformation: \[ x = u + 5v, \quad y = 2u + 4v \] --- #### Explanation: This problem requires evaluating a double integral over a given region \( R \), which in this case is a parallelogram. The vertices of the parallelogram are: - \( (0,0) \) - \( (1,2) \) - \( (5,4) \) - \( (6,6) \) A linear transformation is provided to simplify the region over which the integral is taken: \[ x = u + 5v \] \[ y = 2u + 4v \] Using this transformation, the problem asks to compute the integral in the new coordinates. The function to be integrated is \( 4x + 2y \).
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