Find 4 for dy dz? y = cot(x) dy · sec x² « · cot x

Q: find dy/dxy=cosx/1+sinx

A: To find the derivative of the given function y  = cos(x)/(1 + sin(x)).Use the quotient rule for…

Q: dy/sec2y=dx/secx

A: Explanation of the answer is as follows

Q: Find y'. cot (1) y = 4 cot O A. O B. -8 csc (*) 4 9 CSC 9

A: Given:; Now,           y'=4cotx9'     =4cotx9'     =-csc2x9x9'      =4-csc2x919     =-49csc2x9

Q: Find 이승 dy dx y=3(secx + tan x)(secx- tan x) 11 ***

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Q: Find dy/dx if 3 (cos y) (sin x) = y

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Q: Let y = cot (csc2x/x3+5). Find

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Q: dy Find dx of xy = x + cot y

A: The given equation is xy=x+cot y  Differentiate both sides  ddxxy=ddxx+ddxcot y y+xdydx=1-csc2ydydx…

Q: sin x Find dy/dx given that y 1+ cos x

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Q: what is y' of y=sin-1(cos x)

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Q: y = csc (x’ + 10x), Find dy/dx O (7x6 + 10) csc (x7 + 10x) cot (x7 + 10x)

A: Given: y=cscx7+10x

Q: Find dy /dx fors catx y-(tanx) +Ccata) (cotA) tanx

A: We use Logarithmic properties and differentiation

Q: Find y". y = 5 cot X

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Q: (Sin ² x - y) dx - tanx dy =o

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Q: Evaluate dy/dx if y = (sec2x - tan2x)/(2cos2x-1)

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Q: 24=y cotx

A: Given differential equation is 2y'=ycotx.......1. We have to find the general solution of the given…

Q: Find dy/dx y = sec u, u = X- COS X -

A: Given : y = -secuu = x-cosx

Q: Find dy/dx y = -sec u, u = x- COS X |

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Q: EX/ Find dy for function y = sin ³x + cos³x dx H.W Aus=3sinex (Sinx-Cox) 2

A: Note:-Since you asked multiple questions, according to our policy we can answer only first question…

Q: 3 Itanz. secxdx

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Q: y = Secx ( sinx+ Cosx)

A: Given, y=secxsinx+cosx And we have to find the dydx.