Find; 1. The nearest standard module if no interference is to occur; 2. The mumber of teeth on each wheel; 3. The necessary width of the pinion; and 4. The load on the bearings of the wheels due to power transmitted.
Find; 1. The nearest standard module if no interference is to occur; 2. The mumber of teeth on each wheel; 3. The necessary width of the pinion; and 4. The load on the bearings of the wheels due to power transmitted.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![The following particulars of a single reduction spur gear are given:
Gear ratio = 10:13;
Distance between centres = 660 mm approximately;
Pinion transmits 500 kW at 1800 r.p.m.;
Involute teeth of standard proportions (addendum = m) with pressure angle of 22.5°;
Permissible normal pressure between teeth = 175 N per mm of width.
Find;
1. The nearest standard module if no interference is to occur;
2. The number of teeth on each wheel;
3. The necessary width of the pinion; and
4. The load on the bearings of the wheels due to power transmitted.
Note,
For minimum number of teeth on the pinion, TP, in order to avoid interference,
m = Required module,
T, = Number of teeth on the pinion,
Te = Number of teeth on the gear,
Dp = Pitch circle diameter of the pinion, and
= Pitch circle diameter of the gear.
Let
DG
G = Tp/TG
= pressure angle
Aw = 1 (1 module)
2. Aw
Tp :
1
1+
G(G
1
+2 sin? o – 1
G
|](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F953dbc5e-185b-4b91-9ca0-40c4eb259a44%2Fc8e6f5e2-fa7a-41b6-991d-8eb70593e045%2Fc2iw56d_processed.png&w=3840&q=75)
Transcribed Image Text:The following particulars of a single reduction spur gear are given:
Gear ratio = 10:13;
Distance between centres = 660 mm approximately;
Pinion transmits 500 kW at 1800 r.p.m.;
Involute teeth of standard proportions (addendum = m) with pressure angle of 22.5°;
Permissible normal pressure between teeth = 175 N per mm of width.
Find;
1. The nearest standard module if no interference is to occur;
2. The number of teeth on each wheel;
3. The necessary width of the pinion; and
4. The load on the bearings of the wheels due to power transmitted.
Note,
For minimum number of teeth on the pinion, TP, in order to avoid interference,
m = Required module,
T, = Number of teeth on the pinion,
Te = Number of teeth on the gear,
Dp = Pitch circle diameter of the pinion, and
= Pitch circle diameter of the gear.
Let
DG
G = Tp/TG
= pressure angle
Aw = 1 (1 module)
2. Aw
Tp :
1
1+
G(G
1
+2 sin? o – 1
G
|
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