Find; 1. The nearest standard module if no interference is to occur; 2. The mumber of teeth on each wheel; 3. The necessary width of the pinion; and 4. The load on the bearings of the wheels due to power transmitted.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Question
The following particulars of a single reduction spur gear are given:
Gear ratio = 10:13;
Distance between centres = 660 mm approximately;
Pinion transmits 500 kW at 1800 r.p.m.;
Involute teeth of standard proportions (addendum = m) with pressure angle of 22.5°;
Permissible normal pressure between teeth = 175 N per mm of width.
Find;
1. The nearest standard module if no interference is to occur;
2. The number of teeth on each wheel;
3. The necessary width of the pinion; and
4. The load on the bearings of the wheels due to power transmitted.
Note,
For minimum number of teeth on the pinion, TP, in order to avoid interference,
m = Required module,
T, = Number of teeth on the pinion,
Te = Number of teeth on the gear,
Dp = Pitch circle diameter of the pinion, and
= Pitch circle diameter of the gear.
Let
DG
G = Tp/TG
= pressure angle
Aw = 1 (1 module)
2. Aw
Tp :
1
1+
G(G
1
+2 sin? o – 1
G
|
Transcribed Image Text:The following particulars of a single reduction spur gear are given: Gear ratio = 10:13; Distance between centres = 660 mm approximately; Pinion transmits 500 kW at 1800 r.p.m.; Involute teeth of standard proportions (addendum = m) with pressure angle of 22.5°; Permissible normal pressure between teeth = 175 N per mm of width. Find; 1. The nearest standard module if no interference is to occur; 2. The number of teeth on each wheel; 3. The necessary width of the pinion; and 4. The load on the bearings of the wheels due to power transmitted. Note, For minimum number of teeth on the pinion, TP, in order to avoid interference, m = Required module, T, = Number of teeth on the pinion, Te = Number of teeth on the gear, Dp = Pitch circle diameter of the pinion, and = Pitch circle diameter of the gear. Let DG G = Tp/TG = pressure angle Aw = 1 (1 module) 2. Aw Tp : 1 1+ G(G 1 +2 sin? o – 1 G |
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