Find 0 in degrees. 17 [?] degrees
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
Related questions
Question
![The image depicts a right triangle with the objective to find the angle \(\theta\) in degrees.
### Diagram Details:
- The triangle is a right-angled triangle, indicated by the square at one vertex.
- The vertical side (opposite the right angle) is labeled with the length 8.
- The hypotenuse (diagonal side) is labeled with the length 17.
- The angle \(\theta\) is located at the vertex opposite the vertical side.
- The problem asks to find \(\theta\) in degrees, with a placeholder for the answer: \([?] \text{ degrees}\).
### Explanation:
This is a trigonometry problem where you use the sine function:
\[
\sin(\theta) = \frac{\text{opposite side}}{\text{hypotenuse}} = \frac{8}{17}
\]
To find \(\theta\), apply the inverse sine function:
\[
\theta = \sin^{-1}\left(\frac{8}{17}\right)
\]
Calculate \(\theta\) to find its value in degrees.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6f2c9438-5a89-4288-b691-8fe1dc913be9%2Fa2a40e6a-89e0-44d6-af02-2a3cbd770d91%2Fzlyw67h_processed.png&w=3840&q=75)
Transcribed Image Text:The image depicts a right triangle with the objective to find the angle \(\theta\) in degrees.
### Diagram Details:
- The triangle is a right-angled triangle, indicated by the square at one vertex.
- The vertical side (opposite the right angle) is labeled with the length 8.
- The hypotenuse (diagonal side) is labeled with the length 17.
- The angle \(\theta\) is located at the vertex opposite the vertical side.
- The problem asks to find \(\theta\) in degrees, with a placeholder for the answer: \([?] \text{ degrees}\).
### Explanation:
This is a trigonometry problem where you use the sine function:
\[
\sin(\theta) = \frac{\text{opposite side}}{\text{hypotenuse}} = \frac{8}{17}
\]
To find \(\theta\), apply the inverse sine function:
\[
\theta = \sin^{-1}\left(\frac{8}{17}\right)
\]
Calculate \(\theta\) to find its value in degrees.
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