Finally we need to get zeros above the 1 in row 3. To get a zero in row 1, column 3 we can simply add 2 and put the result in row 2. 100 1/5 X 0 1 0 -2/5 X 0 0 1 1/5 -13/5 Note that the left side of the augmented matrix is now the identity matrix. Give the resulting inverse matrix below. (If the inverse does not exist, enter DNE into any cell.) 6 -5 10-1 0 -1 01 2 01 00 1 1/5 2/5 -13/5, X - 1/5 2/5
Finally we need to get zeros above the 1 in row 3. To get a zero in row 1, column 3 we can simply add 2 and put the result in row 2. 100 1/5 X 0 1 0 -2/5 X 0 0 1 1/5 -13/5 Note that the left side of the augmented matrix is now the identity matrix. Give the resulting inverse matrix below. (If the inverse does not exist, enter DNE into any cell.) 6 -5 10-1 0 -1 01 2 01 00 1 1/5 2/5 -13/5, X - 1/5 2/5
Chapter12: Sequences, Series And Binomial Theorem
Section12.4: Binomial Theorem
Problem 12.78TI: Find the coefficient of the x4 term of (x+2)7.
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Transcribed Image Text:Step 5
Finally we need to get zeros above the 1 in row 3. To get a zero in row 1, column 3 we can simply add row 3 to row 1 and put the result in row 1. To get a zero in row 2, column 3 we can add -2 times row 3 to row
2 and put the result in row 2.
100
X
1/5
0 1 0 -2/5
X
-13/5
0 0 1 1/5
Note that the left side of the augmented matrix is now the identity matrix. Give the resulting inverse matrix below. (If the inverse does not exist, enter DNE into any cell.)
6
10-1 0-1
01 2 0 1
-5
00 1 1/5 2/5 -13/5,
000
X
-
1/5
2/5
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