Finally we need to get zeros above the 1 in row 3. To get a zero in row 1, column 3 we can simply add 2 and put the result in row 2. 100 1/5 X 0 1 0 -2/5 X 0 0 1 1/5 -13/5 Note that the left side of the augmented matrix is now the identity matrix. Give the resulting inverse matrix below. (If the inverse does not exist, enter DNE into any cell.) 6 -5 10-1 0 -1 01 2 01 00 1 1/5 2/5 -13/5, X - 1/5 2/5

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter8: Polynomials
Section8.1: Adding And Subtracting Polynomials
Problem 63HP
Question
100%
Step 5
Finally we need to get zeros above the 1 in row 3. To get a zero in row 1, column 3 we can simply add row 3 to row 1 and put the result in row 1. To get a zero in row 2, column 3 we can add -2 times row 3 to row
2 and put the result in row 2.
100
X
1/5
0 1 0 -2/5
X
-13/5
0 0 1 1/5
Note that the left side of the augmented matrix is now the identity matrix. Give the resulting inverse matrix below. (If the inverse does not exist, enter DNE into any cell.)
6
10-1 0-1
01 2 0 1
-5
00 1 1/5 2/5 -13/5,
000
X
-
1/5
2/5
Transcribed Image Text:Step 5 Finally we need to get zeros above the 1 in row 3. To get a zero in row 1, column 3 we can simply add row 3 to row 1 and put the result in row 1. To get a zero in row 2, column 3 we can add -2 times row 3 to row 2 and put the result in row 2. 100 X 1/5 0 1 0 -2/5 X -13/5 0 0 1 1/5 Note that the left side of the augmented matrix is now the identity matrix. Give the resulting inverse matrix below. (If the inverse does not exist, enter DNE into any cell.) 6 10-1 0-1 01 2 0 1 -5 00 1 1/5 2/5 -13/5, 000 X - 1/5 2/5
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