Finally we need to get zeros above the 1 in row 3. To get a zero in row 1, column 3 we can simply add row 3 to row 1 and put the result in row 1. To get a zero in row 2, column 3 we can add -2 times row 3 to row 2 and put the result in row 2. 1 0 -1 -1 10 0 1/5 0 1 2 1 -5 0 1 0-2/5 1/5 0 0 1 1/5 2/5 -14/5 0 0 1 1/5 2/5 -14/5 Note that the left side of the augmented matrix is now the identity matrix. Give the resulting inverse matrix below. (If the inverse does not exist, enter DNE into any cell.)
Finally we need to get zeros above the 1 in row 3. To get a zero in row 1, column 3 we can simply add row 3 to row 1 and put the result in row 1. To get a zero in row 2, column 3 we can add -2 times row 3 to row 2 and put the result in row 2. 1 0 -1 -1 10 0 1/5 0 1 2 1 -5 0 1 0-2/5 1/5 0 0 1 1/5 2/5 -14/5 0 0 1 1/5 2/5 -14/5 Note that the left side of the augmented matrix is now the identity matrix. Give the resulting inverse matrix below. (If the inverse does not exist, enter DNE into any cell.)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Finally we need to get zeros above the 1 in row 3. To get a zero in row 1, column 3 we can simply add row 3
to row 1 and put the result in row 1. To get a zero in row 2, column 3 we can add -2 times row 3 to row 2
and put the result in row 2.
10-1
0 -1
6.
100
1/5
0 1
2
-5
0 1 0-2/5
1/5
0 0
1 1/5 2/5 -14/5
0 0 1
1/5
2/5
-14/5
Note that the left side of the augmented matrix is now the identity matrix. Give the resulting inverse matrix
below. (If the inverse does not exist, enter DNE into any cell.)
11
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