Finally, determine (x³. - x + 8) and simplify the result. Recall that multiplication is commutative and the order of factors can be rearranged. Note that it is customary to have the exponential term as the last factor. [e"]= (eu) du dx x+8] d dx -x+1 h'(x) = e+³-x+8 dx 1₁+³=x+² Therefore, if h(x) = ex3-x+8, then we have the following result. - de+³x+8] = [

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