Final Grade - An instructor grades exams at 10%; the term paper at 30%; and the final exam at 60%. A student had grades of 70, 86, and 94. respectively. Find the students final average. Use the weighted mean. Use a graphing calculator. Round the solution to one decimal point (if necessary).

Q: メ+1

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Q: A = 6 -2 -2 10 -3 5 1 ---3-0 C=0-2 a = 1, b = [3 08]. -10 1 . B 5 2 11 9 4 4 7 0 0 11

A: We have to solve given Questions.

Q: 5 -100 12 8

A: Solve the given

Q: 40 -50-

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Q: 24 12 XD

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Q: . 3류 - 2층 : 3% +4/3) 1

A:

Q: 12 5(.8)0

A: We can solve given problem by using G.P series.

Q: 10 8/10 + 9 7/12=

A:

Q: 5(18)

A: To find5(18)

Q: 6.4 3

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Q: 2) 36³x=¹

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Q: 1+3+5+7...+1003

A: Sum of n odd numbers, where the last term of the series is (2n – 1), is, Sn = 1 + 3 + 5 + …. + (2n –…

Q: 33/29 b.

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Q: Poove BLO => YQ< B.

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Q: FIND S + 4 (s² – 8S + 6) -

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Q: 1+7/7 + 8

A: Answar would be 10

Q: 4root2*4root2

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Q: 2

A: The Laplace inverse can be found by splitting the expression into three parts as it have power of 3…

Q: sing the geometry of the graph ,evalvate the definite integrals.

A: As this is a multiple subpart question according to the Bartleby Answering rule, only first three…

Q: 9 b and c

A: b) We check if the denominator is 0 for any value of x.  2x2+5=0 2x2=-5 x2=-5/2 (not possible) So…

Q: 7 2 3k+1= [A] k = 2

A: Consider the equation ∑n=273k+1=A We have to find the value of A Expand the summation of left hand…

Q: 4(5+6)=

A: Given: 4(5+6)=

Q: 5. 110 (x + 12)°

A: given alternate exterior angles are equal.

Q: Expand (a −b)4

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Q: 81 (1) 420

A:

Q: Evaluate (33)2

A: Given: 332Power rule amn=am×nSolution:332=33×2=36(33)2=729

Q: 56 10

A: The objective is to evaluate the value for

Q: 5 L s² + 2s – 3

A: We know that, Laplace transform of 1/(s-1) = e^t

Q: 10. Find the sum of the coefficients of (2x– 3)°. c. -6560 d. -5120 а. -5660 b. -6780

A: