Final Answer for a1,a2,and az a, =S° - -1dx +- " 1dx = ? 2n-T 2n (1)()(x) 1 | 1 cos- (1)(1)(x) a1 -1 cos dx = ? (2)(1)(x) 1 f" dx +-| 1cos (2)()(x) dx = ? 1 -1 cos az TE π

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