FINAL ACTIVITY 1. A tension test was performed on a steel specimen having an original diameter of "N" and a gage length of "L" A. PROPORTIONAL LIMIT B. MODULUS OF ELASTICITY C. YIELD STRESS AT 0.2% OFFSET D. ULTIMATE STRESS E. NOMINAL RUPTURE STRESS PLOT THE STRESS-STRAIN DIAGRAM manually AND DETERMINE THE FOLLOWING MECHANICAL PROPERTIES. LOAD (kip) Elongation LOAD (kip) Elongation (in) (in) 0 0 20.0 0.100 1.5 0.0005 21.5 0.28 4.6 0.0015 19.5 0.40 8.0 0.0025 18.5 0.46 11.0 0.0035 17.2 0.50 11.8 0.0050 16.8 0.57 11.8 0.0080 15.1 0.63 12.0 0.0200 14.9 0.65 16.6 0.0400 Use a scale of 1in = 10ksi and 1in = 0.025 in/in. Show your complete solutions.
FINAL ACTIVITY 1. A tension test was performed on a steel specimen having an original diameter of "N" and a gage length of "L" A. PROPORTIONAL LIMIT B. MODULUS OF ELASTICITY C. YIELD STRESS AT 0.2% OFFSET D. ULTIMATE STRESS E. NOMINAL RUPTURE STRESS PLOT THE STRESS-STRAIN DIAGRAM manually AND DETERMINE THE FOLLOWING MECHANICAL PROPERTIES. LOAD (kip) Elongation LOAD (kip) Elongation (in) (in) 0 0 20.0 0.100 1.5 0.0005 21.5 0.28 4.6 0.0015 19.5 0.40 8.0 0.0025 18.5 0.46 11.0 0.0035 17.2 0.50 11.8 0.0050 16.8 0.57 11.8 0.0080 15.1 0.63 12.0 0.0200 14.9 0.65 16.6 0.0400 Use a scale of 1in = 10ksi and 1in = 0.025 in/in. Show your complete solutions.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
SHOW COMPLETE SOLUTION AND NEAT ANSWER
EXAMPLE BELOW FOR THE GIVEN WILL BE USING
FIRST NAME - 12 letters
MIDDLE NAME -9 letters
LAST NAME - 7 Letters
![FINAL ACTIVITY
1. A tension test was
performed on a steel
specimen having an
original diameter of "N"
and a gage length of "L"
A. PROPORTIONAL
LIMIT
B. MODULUS OF
ELASTICITY
C. YIELD STRESS AT
0.2 % OFFSET
D. ULTIMATE STRESS
E. NOMINAL
RUPTURE
STRESS
PLOT THE STRESS-STRAIN
DIAGRAM manually AND
DETERMINE THE FOLLOWING
MECHANICAL PROPERTIES.
LOAD (kip) Elongation
LOAD (kip) Elongation
(in)
(in)
0
0
20.0
0.100
1.5
0.0005
21.5
0.28
4.6
0.0015
19.5
0.40
8.0
0.0025
18.5
0.46
11.0
0.0035
17.2
0.50
11.8
0.0050
16.8
0.57
11.8
0.0080
15.1
0.63
12.0
0.0200
14.9
0.65
16.6
0.0400
Use a scale of 1in = 10ksi and 1in = 0.025
in/in. Show your complete solutions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4404817c-5265-442d-b185-2c6a2f3fda3a%2F893bb1e1-72e5-4758-a8b4-e581efdd0b2c%2Ft1kj43f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:FINAL ACTIVITY
1. A tension test was
performed on a steel
specimen having an
original diameter of "N"
and a gage length of "L"
A. PROPORTIONAL
LIMIT
B. MODULUS OF
ELASTICITY
C. YIELD STRESS AT
0.2 % OFFSET
D. ULTIMATE STRESS
E. NOMINAL
RUPTURE
STRESS
PLOT THE STRESS-STRAIN
DIAGRAM manually AND
DETERMINE THE FOLLOWING
MECHANICAL PROPERTIES.
LOAD (kip) Elongation
LOAD (kip) Elongation
(in)
(in)
0
0
20.0
0.100
1.5
0.0005
21.5
0.28
4.6
0.0015
19.5
0.40
8.0
0.0025
18.5
0.46
11.0
0.0035
17.2
0.50
11.8
0.0050
16.8
0.57
11.8
0.0080
15.1
0.63
12.0
0.0200
14.9
0.65
16.6
0.0400
Use a scale of 1in = 10ksi and 1in = 0.025
in/in. Show your complete solutions.
![Problem No.1
Where:
N= 0.03n
n = no. of letters in your first name, middle name and last name.
example: Marjorie Sibonga Aying
N=0.03*20=0.60 inches
if the value of 0.03n exceeds 0.70, use 0.60, if below 0.50, use 0.50.
Example 1: 0.03n = 0.75, use 0.60 as your diameter.
Example 2: 0.03n = 0.47, use 0.50.
Example 3: 0.03n= 0.65, as is.
Where:
L= 4N
Example: L = 4 (0.60) = 2.4in
-nothing follows-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4404817c-5265-442d-b185-2c6a2f3fda3a%2F893bb1e1-72e5-4758-a8b4-e581efdd0b2c%2F8lorwzl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem No.1
Where:
N= 0.03n
n = no. of letters in your first name, middle name and last name.
example: Marjorie Sibonga Aying
N=0.03*20=0.60 inches
if the value of 0.03n exceeds 0.70, use 0.60, if below 0.50, use 0.50.
Example 1: 0.03n = 0.75, use 0.60 as your diameter.
Example 2: 0.03n = 0.47, use 0.50.
Example 3: 0.03n= 0.65, as is.
Where:
L= 4N
Example: L = 4 (0.60) = 2.4in
-nothing follows-
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