Fill the blank A) 2.000 sin (5t - 9°) at t= 0, 0.01, and 0.1 s. (Round the final answer to four decimal places. Include a minus sign if necessary.) The solution of 2.000 sin (5t-9°) at t=0s is The solution of 2.000 sin (5t-9°) at t= 0.01 s is The solution of 2.000 sin (5t-9°) at t=0.1 s is B) Determine the equivalent impedance of the following, assuming an operating frequency of 20 rad/s. 15.00 kQ in parallel with 1 mH. (Round the final answer to two decimal places.) Report your answer so that all angles are in the range of 0 degrees to positive 180 degrees. The equivalent impedance is • Ω.

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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Fill the blank
A) 2.000 sin (5t - 9°) at t= 0, 0.01, and 0.1 s. (Round the final answer to four
decimal places. Include a minus sign if necessary.)
The solution of 2.000 sin (5t- 9°) at t=0 s is |
The solution of 2.000 sin (5t-9°) at t=0.01 s is
The solution of 2.000 sin (5t-9°) at t=0.1 s is
B) Determine the equivalent impedance of the following,
assuming an operating frequency of 20 rad/s.
15.00 kQ in parallel with 1 mH. (Round the final answer to two decimal places.)
Report your answer so that all angles are in the range of 0 degrees to positive
180 degrees.
The equivalent impedance is |
° QQ.
Transcribed Image Text:Fill the blank A) 2.000 sin (5t - 9°) at t= 0, 0.01, and 0.1 s. (Round the final answer to four decimal places. Include a minus sign if necessary.) The solution of 2.000 sin (5t- 9°) at t=0 s is | The solution of 2.000 sin (5t-9°) at t=0.01 s is The solution of 2.000 sin (5t-9°) at t=0.1 s is B) Determine the equivalent impedance of the following, assuming an operating frequency of 20 rad/s. 15.00 kQ in parallel with 1 mH. (Round the final answer to two decimal places.) Report your answer so that all angles are in the range of 0 degrees to positive 180 degrees. The equivalent impedance is | ° QQ.
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