Fill out table   Expected # Indiv. Observed # Indiv. (Obs – Exp)2 (Obs – Exp)2/Exp FF   22     SS   36     SF   35     Total   93  Χ2=

Q: 2. LOshx-Sin hx1 2. Co

A: We use hyperbolic Trigonometry identies

Q: How do I parameterize the portion from Rei pi/4 to 0?

A:

Q: SHOW THAT : csc² (2 cot¯ /x -1 dx X - 1 Vx +x/x

A:

Q: 115 x y = [ ? ]° Enter

A:

Q: tane cote +- = sin0 + cose %3D 9. Sece csce

A:

Q: amplitude= period phase shift lverhical Snift eauation for each Cunve in terms of Cosine

A: Given,

Q: (12FF35.AE)16 = ( D10 a. (1245981.89)10 Ob. (3244981.78)10 O. (1244991.77)10 O d.(1244981.68)10

A: We need to convert the base 16 number to base 10 number. We will do it by definition of base 16 and…

Q: 3. 4 cos 2 s2-4sin = 5 %3D -

A:

Q: 19. sine = and tan 0 =

A:

Q: a Identify the inproper intergrals an ex plain (briefly) why it is improper () e 5 dX D x-ス ーメー2

A:

Q: cos x = 8/17, 3pi/2<x<2pi. Find cot x

A: cosx=817=BHthrefore by using right angle triangle and Pythagoras theoremH2=B2+P2172=82+P2P=225P=15

Q: 1. sine 12 13 cosine tangent

A:

Q: QUESTION 4 dy Find if da 1- cosh a 1+ cosh a

A:

Q: 21.2 x cot(sin(0.8545)) = O 27.89 O 40.81 O 34.87 O 12.89 O 24.81

A:

Q: tan 0 = 0.8, 500°<0 < 1000° %3D

A: To solve: The equation tan θ=0.8. 500°≤θ≤1000°. Formula used: If tan θ=tan α then θ=nπ+α.…

Q: nontrigonometric for csc(arccos u)=

A: To find csc(arccosu)

Q: Integrate nos. 1 1. f sin sin dx

A:

Q: 12. In a right triangle, the sine of an angle is equal to the cosine of its complement. O True False

A: Please see the explanation below

Q: calcu late an approscimation of with an Sin a ervar of less than 10 イイ

A:

Q: Differentiate sin y = a'

A: Solution

Q: sinA (1+cosA) prove that =2cosecA (1+cosA) sinA

A: sinA1+cosA+1+cosAsinA =sinA·sinA+1+cosA1+cosA1+cosAsinA =sin2A+1+cosA2sinA1+cosA…

Q: Use the sum and difference identities to determine the exact value of the following expression. If…

A:

Q: 37 radians? What is the exact value of sin'(tan g) where g = - 4 %3D

A:

Q: tine the derivative of Ruction?

A: From the given information, The function is y=sin32x

Q: S Arctan2x dx

A: This is to be solved by the technique called integration by parts

Q: r cot VE-tan° V cosº /T VEsin JE dx

A: Given that: ∫cot3x-tan6x.cos6xx.sin3xdx

Q: tanc = 1/3 where  pi<c<3pi/2   what quadrant is 2c on?

A: Given tanC = 1/3  where  π&lt;C&lt;3π/2 To find the quadrant in which 2C lies

Q: Which of the following is equal to arcsin(-V3/2)? -27/3 -T/3 T/3 27/3 ООО

A: