Fill in the missing values to make the equations true. (a) log 5 + log, 8 = 7 (b) log-log 3 = log4 log (c) log, 2 27 = log, 3 log 00 X

Q: Solve for æ: log,( – x + 12) = 2 Write log,( – x + 12) = 2 in expone

A: Given that: log4(-x+12)=2

Q: Solve equation: log:(3x – 1) = 3 Select one: O a. x -3 O b. x-3 O c. x-1/3 Od. x-10/3

A:

Q: Solve : log, (7 + x) = 2 log, 2 O x= 12 x = -3 O x = 13 O x = 3 O x = 11

A: Given Solve : log₂ (7+ x) = 2log₂2

Q: 5. Rewrite as a single logarithm: logs (r) + log, (1) - 3 log, (z - 2))

A: We can solve the problem by applying properties of logarithm.

Q: Simplify:

A:

Q: Solve the equation for x: log, (x-5)+log, (x+3) =1

A: Consider the equation: log9x-5+log9x+3=1. Apply the log property logab+logac=logabc…

Q: (a) log, 8 - log, 5 log, (b) log, 3 + log₂= log₂ 21 (c) - 4log, 3 = log,

A: (a) log38-log35=log3_ (b) log23+log2_=log221 (c) -4log93=log9_ We have to fill in the missing…

Q: Express single logarithm and simplify: 4. as a 3 logą(a + b) + 2 log4(a+ b) – log4c, a +b > 0,c > 0

A: Let's find.

Q: Rewrite the left hand side as an expression of a single logarithm: log3(x-1)-log3(x+2)=2

A: Given,

Q: The Log 24 =

A:

Q: (3x + 1) log6 = (2x-3) log2

A: To solve the equation(3x+1)log6=(2x-3)log2

Q: 64 16 log a 64 + 8 log 64 + 4 log 64 + · · 3

A:

Q: Simplify: 10 log (5x+1)

A: