Fill in the missing symbol in this nuclear chemical equation.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
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### Nuclear Chemistry Exercise

#### Fill in the Missing Symbol in this Nuclear Chemical Equation

Below is a nuclear chemical equation with a missing symbol. Your task is to determine the correct symbol to complete the equation.

\[ \text{ } \]

\[ 
\begin{array}{ccc}
  ^{238}_{92}\text{U} & + & \square \\
  & \rightarrow & ^{239}_{92}\text{U}
\end{array}
\]

### Explanation:

- The equation illustrates a nuclear transformation where Uranium-238 (\( _{92}^{238}\text{U} \)) is converted into Uranium-239 (\( _{92}^{239}\text{U} \)).
- To identify the missing symbol, consider the changes in the mass number and atomic number from the reactants to the products.
- The mass number increases from 238 to 239. 
- The atomic number remains the same (92 in both reactants and products).
- The missing particle must therefore add 1 to the mass number without changing the atomic number. 
- This indicates the addition of a neutron (\( _{0}^{1}\text{n} \)).

### Completed Nuclear Equation

\[ 
\begin{array}{ccc}
  ^{238}_{92}\text{U} & + & ^{1}_{0}\text{n} \\
  & \rightarrow & ^{239}_{92}\text{U}
\end{array}
\]

### Summary

In this nuclear reaction, the missing symbol is a neutron (\( _{0}^{1}\text{n} \)). When a neutron is added to Uranium-238, it converts into Uranium-239.
Transcribed Image Text:### Nuclear Chemistry Exercise #### Fill in the Missing Symbol in this Nuclear Chemical Equation Below is a nuclear chemical equation with a missing symbol. Your task is to determine the correct symbol to complete the equation. \[ \text{ } \] \[ \begin{array}{ccc} ^{238}_{92}\text{U} & + & \square \\ & \rightarrow & ^{239}_{92}\text{U} \end{array} \] ### Explanation: - The equation illustrates a nuclear transformation where Uranium-238 (\( _{92}^{238}\text{U} \)) is converted into Uranium-239 (\( _{92}^{239}\text{U} \)). - To identify the missing symbol, consider the changes in the mass number and atomic number from the reactants to the products. - The mass number increases from 238 to 239. - The atomic number remains the same (92 in both reactants and products). - The missing particle must therefore add 1 to the mass number without changing the atomic number. - This indicates the addition of a neutron (\( _{0}^{1}\text{n} \)). ### Completed Nuclear Equation \[ \begin{array}{ccc} ^{238}_{92}\text{U} & + & ^{1}_{0}\text{n} \\ & \rightarrow & ^{239}_{92}\text{U} \end{array} \] ### Summary In this nuclear reaction, the missing symbol is a neutron (\( _{0}^{1}\text{n} \)). When a neutron is added to Uranium-238, it converts into Uranium-239.
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