Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Nuclear Chemistry Exercise
#### Fill in the Missing Symbol in this Nuclear Chemical Equation
Below is a nuclear chemical equation with a missing symbol. Your task is to determine the correct symbol to complete the equation.
\[ \text{ } \]
\[
\begin{array}{ccc}
^{238}_{92}\text{U} & + & \square \\
& \rightarrow & ^{239}_{92}\text{U}
\end{array}
\]
### Explanation:
- The equation illustrates a nuclear transformation where Uranium-238 (\( _{92}^{238}\text{U} \)) is converted into Uranium-239 (\( _{92}^{239}\text{U} \)).
- To identify the missing symbol, consider the changes in the mass number and atomic number from the reactants to the products.
- The mass number increases from 238 to 239.
- The atomic number remains the same (92 in both reactants and products).
- The missing particle must therefore add 1 to the mass number without changing the atomic number.
- This indicates the addition of a neutron (\( _{0}^{1}\text{n} \)).
### Completed Nuclear Equation
\[
\begin{array}{ccc}
^{238}_{92}\text{U} & + & ^{1}_{0}\text{n} \\
& \rightarrow & ^{239}_{92}\text{U}
\end{array}
\]
### Summary
In this nuclear reaction, the missing symbol is a neutron (\( _{0}^{1}\text{n} \)). When a neutron is added to Uranium-238, it converts into Uranium-239.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc0633024-a4bc-4f66-b9e9-fd2e8bdcc354%2Fc94a0ff5-a057-4dd8-a979-74fed0559faa%2Fy20jan9_processed.png&w=3840&q=75)
Transcribed Image Text:### Nuclear Chemistry Exercise
#### Fill in the Missing Symbol in this Nuclear Chemical Equation
Below is a nuclear chemical equation with a missing symbol. Your task is to determine the correct symbol to complete the equation.
\[ \text{ } \]
\[
\begin{array}{ccc}
^{238}_{92}\text{U} & + & \square \\
& \rightarrow & ^{239}_{92}\text{U}
\end{array}
\]
### Explanation:
- The equation illustrates a nuclear transformation where Uranium-238 (\( _{92}^{238}\text{U} \)) is converted into Uranium-239 (\( _{92}^{239}\text{U} \)).
- To identify the missing symbol, consider the changes in the mass number and atomic number from the reactants to the products.
- The mass number increases from 238 to 239.
- The atomic number remains the same (92 in both reactants and products).
- The missing particle must therefore add 1 to the mass number without changing the atomic number.
- This indicates the addition of a neutron (\( _{0}^{1}\text{n} \)).
### Completed Nuclear Equation
\[
\begin{array}{ccc}
^{238}_{92}\text{U} & + & ^{1}_{0}\text{n} \\
& \rightarrow & ^{239}_{92}\text{U}
\end{array}
\]
### Summary
In this nuclear reaction, the missing symbol is a neutron (\( _{0}^{1}\text{n} \)). When a neutron is added to Uranium-238, it converts into Uranium-239.
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