Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![? g Ca (₂04 = 5.92g Na₂C₂04 X
X
Imol Na₂ (204
134 g Na₂ (₂04
9 Ca(204 = 5.92 g cacd₂ x Imol CaCl₂
110.98 g
X
Amount of cach, remained =
Imol Ca(104
128.097 9 Ca(₂04
Imol Na₂C104 Imol ca₂04
? g of call₂ Uhed = 5.929 Na₂ (₂04 X
Imol Ca(₂04 128.097 9ca₂04 = 6.8331 g cac ₂04
Imol Na₂ (₂04 Imol Ca(₂04
X
Na₂1204 is the limiting reactant because the theoritical yield calculated
Uring mass of Na₂ (204 in less than that of the value calculated using mass
of Cact₂.
X
Imol Na₂ (₂04
1349 Na₂ (₂04
= 5.659296ac₂04
X
Imol Cac12 10.989
X
Imol Na₂ (₂04 Imol CaCl₂
= 4.9029899
=4.9029979
Amount of Cachs given.
5.92 g
4.902997 g
1.017003 g
-- 1.017 g of Cactz is left over after the reaction is complete.
No Na₂604 remained after the reaction is complete because it is the
limiting realtant and completely consumed.
Amount of cach₂ used](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb86d2c65-27cb-4214-b41a-ba7b61245fb5%2Feb64769f-cced-41ab-96b8-c9457c1f1163%2Fnoj7hk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:? g Ca (₂04 = 5.92g Na₂C₂04 X
X
Imol Na₂ (204
134 g Na₂ (₂04
9 Ca(204 = 5.92 g cacd₂ x Imol CaCl₂
110.98 g
X
Amount of cach, remained =
Imol Ca(104
128.097 9 Ca(₂04
Imol Na₂C104 Imol ca₂04
? g of call₂ Uhed = 5.929 Na₂ (₂04 X
Imol Ca(₂04 128.097 9ca₂04 = 6.8331 g cac ₂04
Imol Na₂ (₂04 Imol Ca(₂04
X
Na₂1204 is the limiting reactant because the theoritical yield calculated
Uring mass of Na₂ (204 in less than that of the value calculated using mass
of Cact₂.
X
Imol Na₂ (₂04
1349 Na₂ (₂04
= 5.659296ac₂04
X
Imol Cac12 10.989
X
Imol Na₂ (₂04 Imol CaCl₂
= 4.9029899
=4.9029979
Amount of Cachs given.
5.92 g
4.902997 g
1.017003 g
-- 1.017 g of Cactz is left over after the reaction is complete.
No Na₂604 remained after the reaction is complete because it is the
limiting realtant and completely consumed.
Amount of cach₂ used
![8. Balanced Chemical Equation
Reaction Type:
At completion of reactions:
Formula of Reactant A
Formula of Reactant B
Formula of Product C
Formula of Product D
Grams of Reactant A
Grams of Reactant B
Grams of Product C
Grams of Product D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb86d2c65-27cb-4214-b41a-ba7b61245fb5%2Feb64769f-cced-41ab-96b8-c9457c1f1163%2Fbfv2kgp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:8. Balanced Chemical Equation
Reaction Type:
At completion of reactions:
Formula of Reactant A
Formula of Reactant B
Formula of Product C
Formula of Product D
Grams of Reactant A
Grams of Reactant B
Grams of Product C
Grams of Product D
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