Fill in the Blank Convert the following cyphertext to plaintext. Let N = 125 and k = 46. Use the simple encryption scheme mentioned in section 6.8. Decrypt the cyphertext c = 71. Provide only the numerical answer. Example 100 not m=100
Fill in the Blank Convert the following cyphertext to plaintext. Let N = 125 and k = 46. Use the simple encryption scheme mentioned in section 6.8. Decrypt the cyphertext c = 71. Provide only the numerical answer. Example 100 not m=100
Computer Networking: A Top-Down Approach (7th Edition)
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ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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![Fill in the Blank
Convert the following cyphertext to plaintext.
Let N = 125 and k = 46. Use the simple encryption scheme mentioned in section 6.8.
Decrypt the cyphertext c = 71.
Provide only the numerical answer. Example 100 not m=100
[Text box for answer input]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F64890eb5-4eb0-4853-894d-dd9980127f88%2Fc10f557f-99af-4e8b-a735-910aacd95ad2%2Fqztfzrl_processed.png&w=3840&q=75)
Transcribed Image Text:Fill in the Blank
Convert the following cyphertext to plaintext.
Let N = 125 and k = 46. Use the simple encryption scheme mentioned in section 6.8.
Decrypt the cyphertext c = 71.
Provide only the numerical answer. Example 100 not m=100
[Text box for answer input]
![**Encryption and Decryption Functions**
Encrypting a plaintext message requires computing a mathematical function with the integer plaintext \( m \) as the input and the ciphertext \( c \) as the output. Decrypting the ciphertext therefore is computing the inverse of the encryption process. Given a ciphertext \( c \), the decryption process must produce the unique plaintext \( m \) whose encryption is \( c \). Suppose that the set of all possible plaintexts comes from a set \( M \), a subset of the integers. Encryption is a function whose domain is \( M \) and whose range is \( C \), the set of all ciphertexts.
Consider a simple cryptosystem in which the set of all possible plaintexts comes from \( \mathbb{Z}_N \) for some integer \( N \). Alice and Bob share a secret number \( k \in \mathbb{Z}_N \). The security of their encryption scheme rests on the assumption that no one besides them knows the number \( k \). To encrypt a plaintext \( m \in \mathbb{Z}_N \), Alice computes:
\[
c = (m + k) \mod N \quad \text{(encryption)}
\]
Alice sends the ciphertext \( c \) to Bob. When Bob receives the ciphertext \( c \), he decrypts \( c \) as follows:
\[
m = (c - k) \mod N \quad \text{(decryption)}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F64890eb5-4eb0-4853-894d-dd9980127f88%2Fc10f557f-99af-4e8b-a735-910aacd95ad2%2Fv0n3oko_processed.png&w=3840&q=75)
Transcribed Image Text:**Encryption and Decryption Functions**
Encrypting a plaintext message requires computing a mathematical function with the integer plaintext \( m \) as the input and the ciphertext \( c \) as the output. Decrypting the ciphertext therefore is computing the inverse of the encryption process. Given a ciphertext \( c \), the decryption process must produce the unique plaintext \( m \) whose encryption is \( c \). Suppose that the set of all possible plaintexts comes from a set \( M \), a subset of the integers. Encryption is a function whose domain is \( M \) and whose range is \( C \), the set of all ciphertexts.
Consider a simple cryptosystem in which the set of all possible plaintexts comes from \( \mathbb{Z}_N \) for some integer \( N \). Alice and Bob share a secret number \( k \in \mathbb{Z}_N \). The security of their encryption scheme rests on the assumption that no one besides them knows the number \( k \). To encrypt a plaintext \( m \in \mathbb{Z}_N \), Alice computes:
\[
c = (m + k) \mod N \quad \text{(encryption)}
\]
Alice sends the ciphertext \( c \) to Bob. When Bob receives the ciphertext \( c \), he decrypts \( c \) as follows:
\[
m = (c - k) \mod N \quad \text{(decryption)}
\]
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