Fill in the blank below. A researcher wants to show the mean from population 1 is less than the mean from population 2 in matched-pairs data. If the observations from sample 1 are X, and the observations from sample 2 are Y,, and d; = X, - Y, then the null hypothesis is H: H =0 and the alternative hypothesis is H,: H 0. A researcher wants to show the mean from population 1 is less than the mean from population 2 in matched-pairs data. If the observations from sample 1 are X, and the observations from sample 2 are Y, and d, = X, - Y, then the null hypothesis is Hn: Ha =0 and the alternative hypothesis is H,: p.
Fill in the blank below. A researcher wants to show the mean from population 1 is less than the mean from population 2 in matched-pairs data. If the observations from sample 1 are X, and the observations from sample 2 are Y,, and d; = X, - Y, then the null hypothesis is H: H =0 and the alternative hypothesis is H,: H 0. A researcher wants to show the mean from population 1 is less than the mean from population 2 in matched-pairs data. If the observations from sample 1 are X, and the observations from sample 2 are Y, and d, = X, - Y, then the null hypothesis is Hn: Ha =0 and the alternative hypothesis is H,: p.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A researcher wants to show the mean from population 1 is less than the mean from population 2 in matched-pairs data. If the observations from sample 1 are \(X_i\) and the observations from sample 2 are \(Y_i\), and \(d_i = \bar{X_i} - \bar{Y_i}\), then the null hypothesis is \(H_0: \mu_d = 0\) and the alternative hypothesis is \(H_1: \mu_d\) __ 0.
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A researcher wants to show the mean from population 1 is less than the mean from population 2 in matched-pairs data. If the observations from sample 1 are \(X_i\) and the observations from sample 2 are \(Y_i\), and \(d_i = \bar{X_i} - \bar{Y_i}\), then the null hypothesis is \(H_0: \mu_d = 0\) and the alternative hypothesis is \(H_1: \mu_d < 0\).
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