Fill in each blank with the correct response. The equation 3x + y = 15 has a straight f(x) = as its graph. One point that lies on the graph is (4. ). If we solve the eguation for y and use function notation, we have a meaning that the point ( ) lies on the graph of the function. function For this function, f(4) = The equation 3x + y = 15 has a straight as its graph. One point that lies on the graph is (4, ). If we solve the equation for y and use function notation, we have a function f(x) = . For this function, f(4) = meaning that the point (O.) lies on the graph of the function.

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Fill in each blank with the correct response.
The equation 3x+y = 15 has a straight
f(x) =.
as its graph. One point that lies on the graph is (4,_). If we solve the equation for y and use function notation, we have a
meaning that the point (_,_) lies on the graph of the function.
function
For this function, f(4) =.
The equation 3x + y = 15 has a straight
as its graph. One point that lies on the graph is (4, ). If we solve the equation for y and use function notation, we have a
function f(x) = For this function, f(4) =
meaning that the point ( ) lies on the graph of the function.
Transcribed Image Text:Fill in each blank with the correct response. The equation 3x+y = 15 has a straight f(x) =. as its graph. One point that lies on the graph is (4,_). If we solve the equation for y and use function notation, we have a meaning that the point (_,_) lies on the graph of the function. function For this function, f(4) =. The equation 3x + y = 15 has a straight as its graph. One point that lies on the graph is (4, ). If we solve the equation for y and use function notation, we have a function f(x) = For this function, f(4) = meaning that the point ( ) lies on the graph of the function.
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