·0225mL x.1M = 2,25 × 103 mol NaOH LLS 10 mul Acid 1125×15 D IL * ASSAS t 01125M yej + 70 D 1.129 F wular st = mols Acit + ว A A 10/125001 = (1295) ✓ ' DAS Q 68 12-1.44 A 94.044 1.125×103 = 125 molar map Molar Mass = 106 g/mol pure, ubstances mixed AST, V A A 4x Kl I 2 40096) sp C +25 2. (04) 2 + 20H x(2x2)=111 I olbot C0160+22 080 0 5.2851×15 X 00101 25 (0080+5)/45) (0.03214) = 3.00×1017 4.07252 5.78645×10.5 2.177 32104 2.732×167 (0190142) (.0020)(45) File Home Insert Page Layout Formulas Data Review View Help X Cut Calibri 11 AA >শ• Wrap Text General Copy BIU A Merge & Center $% 900 Format Painter Clipboard E Font Alignment. 5 Number Conditional Format as Formatting Table▾ Г Styles B11 × ✓ fx 22.5 B C D E F G H J K L M N 1 PH 2 Moles NaOH 3 Moles Unknown Acid 4 Molarity Unknown Acid 5 Total Moles Acid 6 Molar Mass of Acid + 7 Initial NaOH (mL) 42.5 8 Initial pH 2.91 9 Volume 1st half 7.5 10 Volume 1st EP 12.5 11 Volume 2nd half 22.5 12 Volume 2nd EP 26.5 13 14 15 16 17 18 19 20 21 22 23 24 Sheet1 + Ready About starting quantities Use about 0.120 g of the unknown diprotic acid dissolved in 100 mL of distilled water. Note the concentration of the standardized NaOH solution All burette readings need to be recorded to two decimal places H4 Diprotic Acid Oxalic Acid Formula H2C2O4 Molecular weight Ka1 Ka2 90 g/mol 6.0 x 10-2 6.1 x 10-5 Malonic Acid H2C3H2O4 104 g/mol 1.5 x 10-3 2.0 x 10-6 Maleic Acid H2C4H2O4 116 g/mol 1.2 x 10-2 5.9 x 10-7 Malic Acid H2C4H4O5 134 g/mol 3.5 x 10-4 6.3 x 10-6 Tartaric Acid H2C4H4O6 150 g/mol 1.0 x 10-3 4.6 x 10-5 (200.8, 8.570) (114.2.4.375) Time: 200 s pH: 8.96 Time: 114 s pH: 5.06 Time() Time (s 300 Include an annotated calculation showing how you determined the K₁ and Kǝz (i.e. How did you find Kai and Ka2?). Provide a percent error comparing your experimental molar mass to the accepted value.
·0225mL x.1M = 2,25 × 103 mol NaOH LLS 10 mul Acid 1125×15 D IL * ASSAS t 01125M yej + 70 D 1.129 F wular st = mols Acit + ว A A 10/125001 = (1295) ✓ ' DAS Q 68 12-1.44 A 94.044 1.125×103 = 125 molar map Molar Mass = 106 g/mol pure, ubstances mixed AST, V A A 4x Kl I 2 40096) sp C +25 2. (04) 2 + 20H x(2x2)=111 I olbot C0160+22 080 0 5.2851×15 X 00101 25 (0080+5)/45) (0.03214) = 3.00×1017 4.07252 5.78645×10.5 2.177 32104 2.732×167 (0190142) (.0020)(45) File Home Insert Page Layout Formulas Data Review View Help X Cut Calibri 11 AA >শ• Wrap Text General Copy BIU A Merge & Center $% 900 Format Painter Clipboard E Font Alignment. 5 Number Conditional Format as Formatting Table▾ Г Styles B11 × ✓ fx 22.5 B C D E F G H J K L M N 1 PH 2 Moles NaOH 3 Moles Unknown Acid 4 Molarity Unknown Acid 5 Total Moles Acid 6 Molar Mass of Acid + 7 Initial NaOH (mL) 42.5 8 Initial pH 2.91 9 Volume 1st half 7.5 10 Volume 1st EP 12.5 11 Volume 2nd half 22.5 12 Volume 2nd EP 26.5 13 14 15 16 17 18 19 20 21 22 23 24 Sheet1 + Ready About starting quantities Use about 0.120 g of the unknown diprotic acid dissolved in 100 mL of distilled water. Note the concentration of the standardized NaOH solution All burette readings need to be recorded to two decimal places H4 Diprotic Acid Oxalic Acid Formula H2C2O4 Molecular weight Ka1 Ka2 90 g/mol 6.0 x 10-2 6.1 x 10-5 Malonic Acid H2C3H2O4 104 g/mol 1.5 x 10-3 2.0 x 10-6 Maleic Acid H2C4H2O4 116 g/mol 1.2 x 10-2 5.9 x 10-7 Malic Acid H2C4H4O5 134 g/mol 3.5 x 10-4 6.3 x 10-6 Tartaric Acid H2C4H4O6 150 g/mol 1.0 x 10-3 4.6 x 10-5 (200.8, 8.570) (114.2.4.375) Time: 200 s pH: 8.96 Time: 114 s pH: 5.06 Time() Time (s 300 Include an annotated calculation showing how you determined the K₁ and Kǝz (i.e. How did you find Kai and Ka2?). Provide a percent error comparing your experimental molar mass to the accepted value.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The question and infromation should all be there to answer question. the Answer should be malonic acid. Also Please write the steps and answers without using any computer commands or scripts, just write it normal.
Transcribed Image Text:·0225mL x.1M = 2,25 × 103 mol NaOH
LLS 10 mul Acid
1125×15
D
IL
*
ASSAS
t
01125M
yej
+
70
D
1.129
F
wular st
=
mols Acit
+
ว
A
A
10/125001 = (1295)
✓
'
DAS
Q
68
12-1.44
A
94.044
1.125×103 = 125
molar map
Molar Mass = 106 g/mol
pure, ubstances mixed
AST, V
A
A
4x Kl
I 2
40096) sp
C
+25
2. (04) 2 +
20H
x(2x2)=111
I
olbot
C0160+22
080
0
5.2851×15
X
00101
25
(0080+5)/45)
(0.03214)
= 3.00×1017
4.07252
5.78645×10.5
2.177 32104
2.732×167
(0190142)
(.0020)(45)
Transcribed Image Text:File
Home
Insert
Page Layout
Formulas Data Review
View
Help
X Cut
Calibri
11 AA
>শ•
Wrap Text
General
Copy
BIU A
Merge & Center
$% 900
Format Painter
Clipboard
E
Font
Alignment.
5
Number
Conditional Format as
Formatting Table▾
Г
Styles
B11
×
✓
fx 22.5
B
C
D
E
F
G
H
J
K
L
M
N
1 PH
2 Moles NaOH
3 Moles Unknown Acid
4 Molarity Unknown Acid
5 Total Moles Acid
6 Molar Mass of Acid
+
7 Initial NaOH (mL)
42.5
8 Initial pH
2.91
9 Volume 1st half
7.5
10 Volume 1st EP
12.5
11 Volume 2nd half
22.5
12 Volume 2nd EP
26.5
13
14
15
16
17
18
19
20
21
22
23
24
Sheet1
+
Ready
About starting quantities
Use about 0.120 g of the unknown diprotic acid dissolved in 100 mL of distilled water.
Note the concentration of the standardized NaOH solution
All burette readings need to be recorded to two decimal places
H4
Diprotic Acid
Oxalic Acid
Formula
H2C2O4
Molecular weight
Ka1
Ka2
90 g/mol
6.0 x 10-2
6.1 x 10-5
Malonic Acid
H2C3H2O4
104 g/mol
1.5 x 10-3
2.0 x 10-6
Maleic Acid
H2C4H2O4
116 g/mol
1.2 x 10-2
5.9 x 10-7
Malic Acid
H2C4H4O5
134 g/mol
3.5 x 10-4
6.3 x 10-6
Tartaric Acid
H2C4H4O6
150 g/mol
1.0 x 10-3
4.6 x 10-5
(200.8, 8.570)
(114.2.4.375)
Time: 200 s
pH: 8.96
Time: 114 s
pH: 5.06
Time()
Time (s
300
Include an annotated calculation showing how you determined the K₁ and Kǝz (i.e. How
did you find Kai and Ka2?).
Provide a percent error comparing your experimental molar mass to the
accepted value.
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