Figure P8.48 100 Ω 20 Ω 12 2 t = 0 300 V 2 mH 5 µF
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Question
The switch in the circuit in (Figure 1) has been in position a for a long time. At t=0, the switch moves instantaneously to position b.
Pt A. What is the initial value of va?
Pt B. What is the initial value of dva/dt?
Pt C. What is the numerical expression for va(t) for t≥0?
![Figure P8.48
100 Ω
20 Ω
12 2
t = 0
300 V
2 mH
5 µF](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F73b9308d-bbee-4bd0-bf5e-6d7b5798879d%2F7bce4880-3b0f-4736-a1ac-be2350694705%2Fq6se0m_processed.png&w=3840&q=75)
Transcribed Image Text:Figure P8.48
100 Ω
20 Ω
12 2
t = 0
300 V
2 mH
5 µF
![-8000t
O -600e
cos(6000t) – 100e-8000t
sin(6000t)V
-8000t
O -300e-8000t
cos(6000t) – 100e
sin(6000t)V
-8000t
-8000t
O -300e
cos(6000t) – 200e
sin(6000t)V
O -300e-8000t
cos(6000t) + 200e-8000£
sin(6000t)V
-8000t
-8000t
O -600e
cos(6000t) + 200e
sin(6000t)V
-8000t
O -300e
cos(6000t) + 100e-8000t
sin(6000t)V
O -600e
-8000t
cos(6000t) – 200e
-8000t
sin(6000t)V
-8000t
O -600e
cos(6000t) + 100e-8000t
sin(6000t)V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F73b9308d-bbee-4bd0-bf5e-6d7b5798879d%2F7bce4880-3b0f-4736-a1ac-be2350694705%2F7jgf654_processed.png&w=3840&q=75)
Transcribed Image Text:-8000t
O -600e
cos(6000t) – 100e-8000t
sin(6000t)V
-8000t
O -300e-8000t
cos(6000t) – 100e
sin(6000t)V
-8000t
-8000t
O -300e
cos(6000t) – 200e
sin(6000t)V
O -300e-8000t
cos(6000t) + 200e-8000£
sin(6000t)V
-8000t
-8000t
O -600e
cos(6000t) + 200e
sin(6000t)V
-8000t
O -300e
cos(6000t) + 100e-8000t
sin(6000t)V
O -600e
-8000t
cos(6000t) – 200e
-8000t
sin(6000t)V
-8000t
O -600e
cos(6000t) + 100e-8000t
sin(6000t)V
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