Figure P6 shows a body of mass m¡ which is supported by a spring of stiffness k, anc absorber consisting of a mass m2 and a spring of stiffness k2 is attached to the body as which results in a resonant frequency at 140 Hz. How many such absorber absorbers which is exerted by an Harmonic force F, cOS mt. An undamped dynamic vibration shows a violent resonance at 152 Hz. As a trial remedy a vibration absorber is attached shown. Derive an expression for the amplitude of the vibration of the body. The body Problem 6 are required if no resonance is to Occur between 120 Hz and 180 Hz. F.cos ot k1 mi F(t)=F;cos ot X1 m1 mi F(t)=F2coS ot m2 k2 k2 -Absorber k/2 k/2 m2 m2 Figure P7 Figure P5 Figure P6

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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shown. Derive an expression for the amplitude of the vibration of the body. The body
absorber consisting of a mass m2 and a spring of stiffness k2 is attached to the body as
shows a violent resonance at 152 Hz. As a trial remedy a vibration absorber is attached
which is exerted by an Harmonic force F, cOS mt. An undamped dynamic vibration
Figure P6 shows a body of mass m¡ which is supported by a spring of stiffness kį anc
which results in a resonant frequency at 140 Hz. How many such absorber absorbers
Problem 6
are required if no resonance is to occur between 120 Hz and 180 Hz.
F.cos ot
k1
F(t)=F;cos ot
X1
mi
F(t)=F;cos wt
m2
k2
k/2
k/2
-Absorber
m2
m2
Figure P7
Figure P5
Figure P6
WW
É FWW
Transcribed Image Text:shown. Derive an expression for the amplitude of the vibration of the body. The body absorber consisting of a mass m2 and a spring of stiffness k2 is attached to the body as shows a violent resonance at 152 Hz. As a trial remedy a vibration absorber is attached which is exerted by an Harmonic force F, cOS mt. An undamped dynamic vibration Figure P6 shows a body of mass m¡ which is supported by a spring of stiffness kį anc which results in a resonant frequency at 140 Hz. How many such absorber absorbers Problem 6 are required if no resonance is to occur between 120 Hz and 180 Hz. F.cos ot k1 F(t)=F;cos ot X1 mi F(t)=F;cos wt m2 k2 k/2 k/2 -Absorber m2 m2 Figure P7 Figure P5 Figure P6 WW É FWW
Problem 9
Figure
378
Mohd Yunus Hi Ahbllah M7
Two Degree of Freedom-Free Undamped Vibration
of Machines and Vibrations
constant.
Car mass
M,
m.
X2
Car spring
M2
2k
M2
Tyre mass
k2
2m
Tyre stiffness
X2
2k
Figure P10 – Twodegree-of-freedom model of a
vehicle suspension system
Figure P11
Transcribed Image Text:Problem 9 Figure 378 Mohd Yunus Hi Ahbllah M7 Two Degree of Freedom-Free Undamped Vibration of Machines and Vibrations constant. Car mass M, m. X2 Car spring M2 2k M2 Tyre mass k2 2m Tyre stiffness X2 2k Figure P10 – Twodegree-of-freedom model of a vehicle suspension system Figure P11
Problem 10
1 sightly more sophisticated model of a vehicle suspension system is given in Figure
DI0. Write the equations of motion in matrix form. Calculate the natural frequencies
for k;=10° N/m ; k2=10* N/m ; M2=50 kg ; M1=2,000 kg.
Problem 11
Determine the two natural frequencies and mode shapes of the two-mass systems as
STOwn in Figure P11.
4k
k
[o} =
X2
2k
2m
Figure P12
2k
m
Figure P13
Figure P14
WW
E HWW
WWHE HW
Transcribed Image Text:Problem 10 1 sightly more sophisticated model of a vehicle suspension system is given in Figure DI0. Write the equations of motion in matrix form. Calculate the natural frequencies for k;=10° N/m ; k2=10* N/m ; M2=50 kg ; M1=2,000 kg. Problem 11 Determine the two natural frequencies and mode shapes of the two-mass systems as STOwn in Figure P11. 4k k [o} = X2 2k 2m Figure P12 2k m Figure P13 Figure P14 WW E HWW WWHE HW
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