Figure P15.15

Q: A 0.280-kg block along a horizontal track has a speed of 1.70 m/s immediately before colliding with…

A: (a). using conservation of energy, the initial kinetic energy is equal to the final spring energy.…

Q: A 0.220-kg block along a horizontal track has a speed of 1.20 m/s immediately before colliding with…

A: Given Mass of block is m= 0.220 kg Speed of block is v=1.20 m/s Spring constant of spring is k= 4.35…

Q: 14. It is found that a force of 18 N is required to stretch a spring by 0.300 meters from its…

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Q: A wooden block with mass 1.85 kg is placed against a compressed spring at the bottom of a slope…

A: Part A. The distance between point A and B is d=7.55 m. So, according to the given conditions, the…

Q: You have a light spring which obeys Hooke's law. This spring stretches 2.62 cm vertically when a…

A: We have givenSpring streches to distance (x)=2.62 cm=0.0262 mMass of object (m)=2.6 kg

Q: A 10.0-kg block is released from rest at point in the figure below. The track is frictionless except…

A: coefficient of kinetic friction is 0.38Explanation:Hence, coefficient of kinetic friction is 0.38…

Q: A block with mass 0.50 kg is forced against a horizontal spring of negligible mass, compressing the…

A: The objective of this question is to find the coefficient of kinetic friction between the block and…

Q: You have a light spring which obeys Hooke's law. This spring stretches 2.96 cm vertically when a…

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Q: You have a light spring which obeys Hooke's law. This spring stretches 2.84 cm vertically when a…

A:

Q: A block of mass m= 0.28 kg is resting against the spring with force constant K= 250 N/m and…

A: Given: The mass of the object is 0.28 kg. The spring constant is 250 N/m. The compression in the…

Q: A 1.2 kg block is held at rest against a spring with a force constant k = 750 N/m. Initially, the…

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Q: A block of mass m= 0.28 kg is resting against the spring with force constant K= 250 N/m and…

A: We have a block of mass m=0.28 kg which is connected to a spring of force constant K=250 N/m…

Q: You have a light spring which obeys Hooke's law. This spring stretches 2.54 cm vertically when a…

A:

Q: A block of mass 4.00 kg is placed against a horizontal spring of constant k = 835 N/m and pushed so…

A: Elastic potential energy can be defined as the energy stored when an elastic object is stretched or…

Q: You have a light spring which obeys Hooke's law. This spring stretches 3.08 cm vertically when a…

A: Subpart (a): When the spring is stretched by the object, the weight of the object provides the…

Q: You have a light spring which obeys Hooke's law. This spring stretches 2.88 cm vertically when a…

A: The spring force is given as Fs=kx…

Q: A 10.0 kg block is released from point A in the Figure below. The track is friction-less except for…

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Q: A 0.300-kg block along a horizontal track has a speed of 1.30 m/s immediately before colliding with…

A: a)Change in kinetic energy of block is the equal to the potential energy of compressed spring.

Q: A block of mass 2.60 kg is placed against a horizontal spring of constant k = 815 N/m and pushed so…

A: Given values -  Mass = m = 2.6 kg  Spring constant = k = 815 N/m Compression = x = 0.06 m

Q: A block of mass 2.40 kg is placed against a horizontal spring of constant k = 795 N/h and pushed so…

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Q: A bax slides from rest down a frictionless ramp inclined at 40.0° with respect to the horizontal and…

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Q: A box slides from rest down a frictionless ramp inclined at 40.0° with respect to the horizontal and…

A: Given- Mass of box m=12 kgspring constant k=4×104 N/mDistance d=3 mInitial velocity vi=0final…

Q: A pen contains a spring with a spring constant of 240 N/m. When the tip of the pen is in its…

A: Given dataThe spring constant of the spring is: k = 240 N/mThe initial compression length of the…

Q: If a 4-kg block is placed against the spring and the spring is released, what will be the speed of…

A: GIVEN: Mass of block =4 kg For the spring  Work done =12kx2 where k is spring constant            x…

Q: A box of mass m=125 kg on a horizontal frictionless surface is pressed against (but is not attached…

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Q: You push a 2.00 kg block against a horizontal spring, compressing the spring by 15.0 cm. Then you…

A: Given Mass of block is m= 2.00 kg Compressed distance of spring is x=15.0 cm=0.15 m Spring constant…

Q: A 0.200-kg block along a horizontal track has a speed of 1.60 m/s immediately before colliding with…

A: The mass of the block, m = 0.200 kg. The speed of the block, v = 1.60 m/s. The force constant of the…

Q: A 0.300-kg block along a horizontal track has a speed of 1.60 m/s immediately before colliding with…

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Q: The 5.00 kg object shown below is released from rest at a height of 7.0 m on a curved frictionless…

A: Given,  m=5 kg h=7 m k= 500 N/m g= 9.8 m/s²

Q: A moving 2.90 kg block collides with a horizontal spring whose spring constant is 327 N/m.The block…

A:

Q: You have a light spring which obeys Hooke's law. This spring stretches 2.56 cm vertically when a…

A: Given       Mass of the object (m) = 3.00 kg        Stretching of spring (∆x) = 2.56 cm

Q: A horizontal spring-mass system has low friction, spring stiffness 230 N/m, and mass 0.5 kg. The…

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Q: You have a light spring which obeys Hooke's law. This spring stretches 3.04 cm vertically when a…

A: The spring force is given as Fs=kx…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.