Figurem₂5.0 cm 5.0 cm20.0 cmM3m₁X1 of 1Part AWhat is the magnitude of the net gravitational force on the m₁ = 15 kg mass in (Figure 1)? Assume m2 = m3 = 10 kg.Express your answer in newtons using two significant figures.► View Available Hint(s)IVE ΑΣΦF = 1.068.10SubmitPart BX Incorrect; Try Again0 = 90Previous AnswersSubmit5- 10 kg.What is the direction of the net gravitational force on the m₁ = 15 kg mass in the figure? Assume m2 = m3 =Express your answer in degrees using two significant figures.► View Available Hint(s)above the +x-axisPrevious AnswersCorrect< Return to Assignment?Provide FeedbackN

Name: Figurem₂5.0 cm 5.0 cm20.0 cmM3m₁X1 of 1Part AWhat is the magnitude of
Uploaded: 2024-03-20T06:56:46.000Z
Channel: Bartleby
Description: Figurem₂5.0 cm 5.0 cm20.0 cmM3m₁X1 of 1Part AWhat is the magnitude of the net gravitational force on the m₁ = 15 kg mass in (Figure 1)? Assume m2 = m3 = 10 kg.Express your answer in newtons using two significant figures.► View Available Hint(s)IVE Α

Answered: Image /qna-images/answer/b4bc931f-213c-4d57-a83b-9fce9b781b57.jpg

Science

Physics

Figure m₂ 20.0 cm V 5.0 cm 5.0 cm m₁ m₂ X < 1 of 1 What is the magnitude of the net gravitational force on the m₁ = 15 kg mass in (Figure 1)? Assume m2 = m3 = 10 kg. Express your answer in newtons using two significant figures. ►View Available Hint(s) ID ΑΣΦ 3 F-1.068 10-5 Submit Previous Answers X Incorrect; Try Again ▾ Part B Submit Previous Answers ✓ Correct Ċ E What is the direction of the net gravitational force on the m₁ = 15 kg mass in the figure? Assume m2 = m3 = 10 kg. Express your answer in degrees using two significant figures. ► View Available Hint(s) 0 = 90° above the +x-axis < Return to Assignment www. ? Provide Feedback N

Figure m₂ 20.0 cm V 5.0 cm 5.0 cm m₁ m₂ X < 1 of 1 What is the magnitude of the net gravitational force on the m₁ = 15 kg mass in (Figure 1)? Assume m2 = m3 = 10 kg. Express your answer in newtons using two significant figures. ►View Available Hint(s) ID ΑΣΦ 3 F-1.068 10-5 Submit Previous Answers X Incorrect; Try Again ▾ Part B Submit Previous Answers ✓ Correct Ċ E What is the direction of the net gravitational force on the m₁ = 15 kg mass in the figure? Assume m2 = m3 = 10 kg. Express your answer in degrees using two significant figures. ► View Available Hint(s) 0 = 90° above the +x-axis < Return to Assignment www. ? Provide Feedback N

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: At what altitude above Earth's surface would the gravitational acceleration be 1.50 m/s²? (Take the…

A: Given Data:Gravitational acceleration at a height from the Earth's surface is Radius of the Earth…

Q: The radius of Mars is 3.37 × 106 m, and its mass is 6.42 × 1023 kg. X Part A How long will it take a…

A: Radius, R = 3.37×106 mMass, m = 6.42×10²³ kgHeight, h = 2 mTime, t = ?

Q: A group of astronauts lands on an unknown planet of radius 6.00 x 106 m. They drop a test mass from…

A: According to Newton's laws of motion ,the distance travelled is calculated by using the formula…

Q: Write down an expression for the acceleration of a satellite of mass m in a circular orbit of radius…

A: Solution:-Step 1:

Q: A ball of mass m is found to have a weight Wx on Planet X. Which of the following is a correct…

A: The weight of an object in a planet is the gravitational force exerted by the planet on it. It is…

Q: lease don't provide handwritten solution.... Two forces act on a 4.05 kg object, the…

A: The mass of the object is 4.05 kg.The initial velocity of the object is 0 m/s.The time interval is…

Q: A)Find the magnitude of the gravitational force (in N) between a planet with mass 8.75 ✕ 1024 kg and…

A: It is given that, mp=8.75×1024 kgmm=2.30×1022 kgr=2.40×108 m

Q: A metal box having a mass of 100.0kg is pulled along a level plane, at uniform speed, by a…

A: Answer:- Given Mass of a metal box(m) = 100.0 kg At uniform Speed by a horizontal rope applying a…

Q: hypothetical planet has a mass 2.68 times that of Earth, but the same radius. What is g near its…

A: The acceleration due to gravity on the surface of a planet of mass M and radius R is given g =…

Q: 12. Which of the following statements is not correct? a. The weight of a body on Earth is a measure…

Q: A physicist has just discovered a new kind of particle. The force between two of them is F = -b/r,…

A: F=-br F is force having units=kg m/s2 r is distance having unit metre(m) so units of b will be…

Q: Figure E 4 ft -X P -2ft- B ISAS T 2 ft 3 ft < 1 of

A: P = 660 lb.

Q: Three forces act on point P. Force A equals 80.0 N, 60.0°. Force B equals 70.0 N, 0.0°. Force C…

Q: SKetch for graph of g against

Q: Four masses are at the vertices of a square. Find the magnitude of the gravitational force on the…

Q: a) Find the magnitude of the gravitational force between a planet with the mass 7.50 x 10^24 Kg and…

A: Given: The mass value of the planet is 7.50 x 10^24Kg The mass value of the moon is 2.70 x 10^22 Kg…

Q: A planet has a mass of 6.90 × 1023 kg and a radius of 2.89 × 106 m. (a) What is the acceleration due…

A: The mass of the planet (M) = 6.90*1023 Kg and radius of the planet (R) = 2.89 × 106 m now we known…

Q: Planet X has a radius of 6.00×10^7 m and an unknown mass. When a woman of mass 65.0 kg weighs…

A: Given data: The radius of planet is r=6.00x107 m. The mass of woman is m=65 kg. The distance from…

Q: Four masses 2.8 kg each, are positioned at the corners of an square with side 2.8 m. Determine the x…

A: The gravitational force acting between the two masses M and m is calculated by using the formula…

Q: Europa orbits Jupiter at a distance of 6.7 x 108 m from Jupiter's cloudtops (the surface of the…

Q: Every few months, memes circulate claiming that certain alignments of the planets with the Earth…

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: At what altitude above Earth's surface would the gravitational acceleration be 4.40 m/s2? (Take the…

A: Earth's radius is R=6370 km Gravitational acceleration at height h is g'=4.40 m/s2 Gravitational…

Q: he earth’s mass is 5.972x1024 kgs and the earth’s radius is 6371 kms, determine the altitude of a…

A: Given: M=5.972*1024 kgR=6371 km = 6.371*106 mgh=9.7 m/s2

Q: If I know the acceleration of gravity is 2 times the coefficient x^2 and x^2 = 5.1591 How do i find…

Q: the earth, what are the magnitude and direction of the force the object exerts on Ihe 10.If an…

A: According to Newton's third law Every action has equal and opposite reaction.

Q: n the year 25 000 the Earth is 1.42x1011 m away from the sun and in a circular orbit, but a year…

Concept explainers

Newton's First Law of Motion

If a very smooth ball is rolled down an inclined surface with zero friction, the ball will continue to roll indefinitely for an infinite time, in an attempt to reach to the same height on the opposite hill!

Topic Video

Question

100%

Figure
m₂
5.0 cm 5.0 cm
20.0 cm
M3
m₁
X
1 of 1
Part A
What is the magnitude of the net gravitational force on the m₁ = 15 kg mass in (Figure 1)? Assume m2 = m3 = 10 kg.
Express your answer in newtons using two significant figures.
► View Available Hint(s)
IVE ΑΣΦ
F = 1.068.10
Submit
Part B
X Incorrect; Try Again
0 = 90
Previous Answers
Submit
5
- 10 kg.
What is the direction of the net gravitational force on the m₁ = 15 kg mass in the figure? Assume m2 = m3 =
Express your answer in degrees using two significant figures.
► View Available Hint(s)
above the +x-axis
Previous Answers
Correct
< Return to Assignment
?
Provide Feedback
N

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Determine the given variables

VIEW

Step 2: Draw free body diagram

VIEW

Step 3: Calculate force on mass m1 due to mass m2 and mass m3

VIEW

Step 4: Calculate net force on mass m1

VIEW

Step 5: Calculate direction of net force

VIEW

Solution

VIEW

Step by step

Solved in 6 steps with 5 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

A)Find the magnitude of the gravitational force (in N) between a planet with mass 8.75 ✕ 1024kg and its moon, with mass 2.30 ✕ 1022 kg, if the average distance between their centers is 2.40 ✕ 108 m. _______N B)What is the moon's acceleration (in m/s2) toward the planet? (Enter the magnitude.) __________m/s^2 C)What is the planet's acceleration (in m/s2) toward the moon? (Enter the magnitude.) _________m/s^2
The magnitude F (in newtons) of a force F and the magnitude G (in newtons) of a force G satisfy the vector equation 2Fi-3Fj+2Gi+2Gj-3i=0 where i and j are the Cartesian unit vectors. What is the value of F? 9 10 3 O 5/60/5 10 06
The Moon has a mass 7.35 x 1022 kg of and a radius of 1740 km. Air resistance can be neglected on the Moon. G = 6.67 x 10-11 m3 kg-1 s-2 is the universal gravitational constant. (a) If a ball is launched upwards from the surface of the moon with an initial speed of 1.15 km/s, what height maximum height above the surface of the moon will it reach? Give your answer in kilometers. (b) What is the escape speed of the moon? Give your answer in km/s.
29. Consider Planet X whose mass and radius are 9.05 x 1025 [kg] and 5.95 x 104 [m], respectively. If the weight of the object on the surface of the Earth is 2940 [N], what is its weight at height 750 [m] from the surface of the Planet X? Note: The gravitational constant is G = : 6.6743 x 10-11 m3 A. 3.70 × 108 [N] C. 4.99 x 108 [N] B. 4.88 x 108 [N] D. 5.12 x 108 [N] Lkg
A new planet named Vulcan has been discovered. Vulcan is a rather large planet with a radius twice that of Earth and a mass three times that of Earth. An astronaut has a mass of 60.0 kg and weighs about 132 lbs. on Earth. If the astronaut is on the planet Vulcan, what is her weight? The following numerical values may be helpful in this question. G = 6.67 ∙10-11 N∙m2/ kg2 Earth’s mass = 5.98 · 1024 kilograms g = 9.80 m/sec2 1 kilometer = 1000 meters
Help me to solve this problem step by step and give answer as a 3 significant figures
The magnitude of the force F is 780 Ib. Express F as a vector in terms of the unit vectors i and j. Identify both the scalar and vector components of F. Y, ft F = 780 Ib | --x, ft 36° A (7,-3) Answers: Vector expression: F = 5) Ib + Scalar components: Fx = Ib, Fy Ib Vector components: Fx = i lb, Fy = j lb
magnitude gravitational force (between a planet with mass 9.00 * 10 ^ 24 and moon, with 2.40 * 10 ^ 22 average distance between their canters 2.10 * 10 ^ 8* m b) ? is the moon's acceleration in m/s^ 2 ) toward the planet(Enter the magnitude. ) m/s^ 2 the planets acceleration (in m/s^ 2 ) the moon?
What is the magnitude of the gravitational acceleration at a height of two earth radius (2RE) above earth surface? Take gravitational acceleration near Earth surface as 9.81 m/s2. Express your answer in m/s2 and enter numerical value only, no units
a) i. b) i. Define gravitational field strength at a point. Determine the mass of the Earth assuming that it is a uniform sphere of radius 6378 km and that the gravitational field strength at the Earth's surface is 9.81 N kg¹¹. Determine the average density of the Earth. iii. Use the mass of the Earth as calculated in part b)i to determine the gravitational field strength due to the Earth at a distance of 3.5 x 108 m from the centre of the Earth. ii. iv. Consider a point X a distance of 3.5 x 108 m from the centre of the Earth and which lies on the line joining the centre of the Earth to the centre of the Moon. c) i. ii. At X the gravitational field strength due to the Moon is equal but opposite to that of the Earth. The mass of the Moon is 7.4 x 10²2 kg. Determine the distance from the centre of the Moon to X and hence determine the distance between the centres of the Earth and Moon. Determine the time in Earth years for the planet Jupiter to complete one orbit of the Sun. Take 1…
PW-3 An elevator motor is capable of lifting a 2,500kg elevator 50.0m with a constant speed in 12.0 seconds. a) Apply Fet ma to find the force needed to lift the elevator. b) Find the power of the elevator motor in watts and in horsepower. (1H.P.-750W) c) If the power of the elevator motor is 200H.P., find the constant speed at which the 2,500kg elevator can be raised. d) If the power of the elevator motor is 200H.P., find the constant speed at which the elevator can be raised if the elevator and its contents have a mass of 4,000kg
Newton's law of universal gravitation is represented by Mm F = G- where F is the gravitational force, M and m are masses, and r is a length. Force has the SI units kg · m/s2. What are the SI units of the proportionality constant G? m3 kg - s2 m kg ·s3 m2 kg · s2 m2 kg · 3