Figure: Circular prismatic rods with negative torques at each end. The circular rod shown has an ultimate shear strength, tult = 8 ksi, and ultimate compressive strength, Oult(comp) = -12 ksi, and an ultimate strength, oult(tensile) = 2 ksi. Which plane will be parallel to the failure plane when torque, T, is increased to failure?
Figure: Circular prismatic rods with negative torques at each end. The circular rod shown has an ultimate shear strength, tult = 8 ksi, and ultimate compressive strength, Oult(comp) = -12 ksi, and an ultimate strength, oult(tensile) = 2 ksi. Which plane will be parallel to the failure plane when torque, T, is increased to failure?
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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I know that the answer is A=A' but I am struggling to completely conceptualize why. The smallest ultimate strength is in tension, so it would fail when that stress is met.
Transcribed Image Text:А
45°
45°
A'
B' C'
Figure: Circular prismatic rods with negative torques at each end.
The circular rod shown has an ultimate shear strength, tult = 8 ksi, and ultimate compressive strength,
Oult(comp) = -12 ksi, and an ultimate strength, oultensile) = 2 ksi. Which plane will be parallel to the failure
plane when torque, T, is increased to failure?
%3D
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