Figure 4. How to correctly measure the siba.. weight hanger carries the required added masses. M₁² (8) = 16,55 Msw (8) Table # 1: Determination of the spring constant K g= 9.80 m/s² xo (cm) = 50 100 150 200 250 MT = Mh + Msw MT (8) MT (kg) F=W=Mrg F (N) 0 xf (cm) 0.6517 1.1417 6.6.5, 0.066.5 1/6:52 0.11 6.5 166.5 0.78 6.5 1.63/7 216.2 0.2165 21217 266,55 02. 266.5 2.6117 Average force constant Kavg Force constant Ktren from the slope of the trendline in the graph % relative difference between Kavg and Ktren Mh: Mass of the weight hanger Msw: Mass of added slotted weights MT: Total Mass W: Weight of hanger plus slotted weights 1₁7 3.3 X = Xf- Xo 4.9 6.9 8 x (cm) X (m) 0 K= the F(N) x(m) K (N/m) 0.2 0.1 6/5/168 2.5ch 0.025 45.068 4on 0.09 40,7925 55 0.055 38.576 36 36 4 7.2 0.072 36.9936|||| Xo: Position of the spring's bottom (unstretched) xf Position of the spring's bottom (stretched) x: Elongation of the spring K: Force constant of the spring
Figure 4. How to correctly measure the siba.. weight hanger carries the required added masses. M₁² (8) = 16,55 Msw (8) Table # 1: Determination of the spring constant K g= 9.80 m/s² xo (cm) = 50 100 150 200 250 MT = Mh + Msw MT (8) MT (kg) F=W=Mrg F (N) 0 xf (cm) 0.6517 1.1417 6.6.5, 0.066.5 1/6:52 0.11 6.5 166.5 0.78 6.5 1.63/7 216.2 0.2165 21217 266,55 02. 266.5 2.6117 Average force constant Kavg Force constant Ktren from the slope of the trendline in the graph % relative difference between Kavg and Ktren Mh: Mass of the weight hanger Msw: Mass of added slotted weights MT: Total Mass W: Weight of hanger plus slotted weights 1₁7 3.3 X = Xf- Xo 4.9 6.9 8 x (cm) X (m) 0 K= the F(N) x(m) K (N/m) 0.2 0.1 6/5/168 2.5ch 0.025 45.068 4on 0.09 40,7925 55 0.055 38.576 36 36 4 7.2 0.072 36.9936|||| Xo: Position of the spring's bottom (unstretched) xf Position of the spring's bottom (stretched) x: Elongation of the spring K: Force constant of the spring
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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How to find the average force constant kavg and will this apply to the others on the bottom
![### Determination of the Spring Constant K
**Average force constant $K_{avg}$:**
$K_{avg} = 1.85$
#### Table #1: Determination of the Spring Constant K
\[ g = 9.80 \, \text{m/s}^2 \]
**Explanation of Variables and Columns:**
**$M_{sh}$:** Mass of the slotted hanger
**$M_{th}$:** Mass of the total hanger
**$M_{sw}$:** Mass of the added slotted weights
**$Mt (kg)$:** Total Mass (Mt = M_{th} + M_{sw})
**F (N):** Force (F = W = Mt \cdot g)
**$x_0 (cm) $:** Position of the spring's bottom (unstretched)
**$x (cn):$** Position of the spring's bottom (stretched)
**$X_f:$** Elongation of the spring ($X_f = x - x_0$)
**K (N/m):** Force constant of the spring (K = F/X_f)
| $ M_{sw} $ (g) | $ M_{sw} $ (kg) | $ M_{t} $ (Kg) | F (N) | $x_0$ (cm) | x (cm) | $ X_f $ (m) | K (N/m) |
|----------------|----------------|---------------|-------|------------|--------|-------------|---------|
| 0 | 0 | 0.0655 | 0.64 | 50 | 50 | 0 | - |
| 50 | 0.05 | 0.1155 | 1.13 | 50 | 55 | 0.050 | 22.6 |
| 100 | 0.1 | 0.1655 | 1.62 | 50 | 65 | 0.060 | 26.7 |
| 150 | 0.15 | 0.2155 | 2.11 | 50 | 70 | 0.070 | 29.7 |
| 200 | 0.2 | 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb15e654-30a5-46a4-8934-d26e13081e17%2Fd9a8fb69-8b41-4a26-82d7-d41f9ba2b532%2Fwbap1tr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Determination of the Spring Constant K
**Average force constant $K_{avg}$:**
$K_{avg} = 1.85$
#### Table #1: Determination of the Spring Constant K
\[ g = 9.80 \, \text{m/s}^2 \]
**Explanation of Variables and Columns:**
**$M_{sh}$:** Mass of the slotted hanger
**$M_{th}$:** Mass of the total hanger
**$M_{sw}$:** Mass of the added slotted weights
**$Mt (kg)$:** Total Mass (Mt = M_{th} + M_{sw})
**F (N):** Force (F = W = Mt \cdot g)
**$x_0 (cm) $:** Position of the spring's bottom (unstretched)
**$x (cn):$** Position of the spring's bottom (stretched)
**$X_f:$** Elongation of the spring ($X_f = x - x_0$)
**K (N/m):** Force constant of the spring (K = F/X_f)
| $ M_{sw} $ (g) | $ M_{sw} $ (kg) | $ M_{t} $ (Kg) | F (N) | $x_0$ (cm) | x (cm) | $ X_f $ (m) | K (N/m) |
|----------------|----------------|---------------|-------|------------|--------|-------------|---------|
| 0 | 0 | 0.0655 | 0.64 | 50 | 50 | 0 | - |
| 50 | 0.05 | 0.1155 | 1.13 | 50 | 55 | 0.050 | 22.6 |
| 100 | 0.1 | 0.1655 | 1.62 | 50 | 65 | 0.060 | 26.7 |
| 150 | 0.15 | 0.2155 | 2.11 | 50 | 70 | 0.070 | 29.7 |
| 200 | 0.2 | 0
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