Figure 4-52 F+y AWV ALLV * C(Capacitance) R (Resistance)
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
![Figure 4-52
F+y
ALLLY
C(Capacitance)
20+4.
R
(Resistance)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff03f8eaa-7224-4d1a-998e-bbaa5add64e6%2F60d5b21a-8147-4d60-bae5-bd4ed7a50a1b%2Fq2h3bj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Figure 4-52
F+y
ALLLY
C(Capacitance)
20+4.
R
(Resistance)
![B-4-10. Consider the liquid-level control system shown in
We assume that the velocity of the power piston (valve)
K₁.x
where K₁ is a positive constant. We also assume that the
change in the inflow rate q, is negatively proportional to the
change in the valve opening y, or
Figure 4-52. The inlet valve is controlled by a hydraulic is proportional to pilot-valve displacement .x. or
integral controller. Assume that the steady-state inflow rate
is and steady-state outflow rate is also, the steady-state
head is , steady-state pilot valve displacement is X = 0,
and steady-state valve position is Y. We assume that the set
point R corresponds to the steady-state head H. The set
point is fixed. Assume also that the disturbance inflow rate
94, which is a small quantity, is applied to the water tank at
= 0. This disturbance causes the head to change from to
H+h. This change results in a change in the outflow rate
by qo. Through the hydraulic controller, the change in head
causes a change in the inflow rate from 0 to + q. (The
integral controller tends to keep the head constant as much
as possible in the presence of disturbances.) We assume that
all changes are of small quantities.
9i= -Kry
dy
dt
where K, is a positive constant.
Assuming the following numerical values for the system,
C = 2m², R = 0.5 sec/m². K₁ = 1 m²/sec
b = 0.75 m.
obtain the transfer function H(s)/Qd(s)|
a = 0.25 m.
K₁ = 4 sec¹](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff03f8eaa-7224-4d1a-998e-bbaa5add64e6%2F60d5b21a-8147-4d60-bae5-bd4ed7a50a1b%2Fpkc3h8h_processed.jpeg&w=3840&q=75)
Transcribed Image Text:B-4-10. Consider the liquid-level control system shown in
We assume that the velocity of the power piston (valve)
K₁.x
where K₁ is a positive constant. We also assume that the
change in the inflow rate q, is negatively proportional to the
change in the valve opening y, or
Figure 4-52. The inlet valve is controlled by a hydraulic is proportional to pilot-valve displacement .x. or
integral controller. Assume that the steady-state inflow rate
is and steady-state outflow rate is also, the steady-state
head is , steady-state pilot valve displacement is X = 0,
and steady-state valve position is Y. We assume that the set
point R corresponds to the steady-state head H. The set
point is fixed. Assume also that the disturbance inflow rate
94, which is a small quantity, is applied to the water tank at
= 0. This disturbance causes the head to change from to
H+h. This change results in a change in the outflow rate
by qo. Through the hydraulic controller, the change in head
causes a change in the inflow rate from 0 to + q. (The
integral controller tends to keep the head constant as much
as possible in the presence of disturbances.) We assume that
all changes are of small quantities.
9i= -Kry
dy
dt
where K, is a positive constant.
Assuming the following numerical values for the system,
C = 2m², R = 0.5 sec/m². K₁ = 1 m²/sec
b = 0.75 m.
obtain the transfer function H(s)/Qd(s)|
a = 0.25 m.
K₁ = 4 sec¹
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