Figure 3: 4. Positive charge is distributed uniformly over each of two spherical volumes with radius R. One sphere of charge is centered at the origin and the other at x' = 2R (see Figure 3). The magnitude and direction of the net electric field due to these two distributions of charge at the following points are: (a)x = 0: Ē = E1 + Ē2 = 0 (True,False) (b)x = 5: E = Ē1 + Ē2 = Ē = E1 + E2 = 4r€0 (2R)2 Q 4r€0 R3 Q (True,False) 4T€0 (R)2 (c)x = R: Rî (True,False) 4TE0 R3 4T€0 R2 E = E1 + Ē2 = E = E1 + E2 (d)x = 2R: Q i +0 (True,False) 4T€0 (2R)2 Ri + 4περ R3 - Ri (e)x = 3R: (True,False) 4περ (3R) 2

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Figure 3:
4. Positive charge is distributed uniformly over each of two spherical volumes with radius R. One sphere of charge is centered at the origin
and the other at x' = 2R (see Figure 3). The magnitude and direction of the net electric field due to these two distributions of charge at the
following points are:
(a)x = 0:
Ē = E1 + Ē2 = 0
(True,False)
(b)x = 5: E = Ē1 + Ē2 =
Ē = E1 + E2 =
4r€0 (2R)2
Q
4r€0 R3
Q
(True,False)
4T€0 (R)2
(c)x = R:
Rî
(True,False)
4TE0 R3
4T€0 R2
E = E1 + Ē2 =
E = E1 + E2
(d)x = 2R:
Q
i +0
(True,False)
4T€0 (2R)2
Ri +
4περ R3
- Ri
(e)x = 3R:
(True,False)
4περ (3R) 2
Transcribed Image Text:Figure 3: 4. Positive charge is distributed uniformly over each of two spherical volumes with radius R. One sphere of charge is centered at the origin and the other at x' = 2R (see Figure 3). The magnitude and direction of the net electric field due to these two distributions of charge at the following points are: (a)x = 0: Ē = E1 + Ē2 = 0 (True,False) (b)x = 5: E = Ē1 + Ē2 = Ē = E1 + E2 = 4r€0 (2R)2 Q 4r€0 R3 Q (True,False) 4T€0 (R)2 (c)x = R: Rî (True,False) 4TE0 R3 4T€0 R2 E = E1 + Ē2 = E = E1 + E2 (d)x = 2R: Q i +0 (True,False) 4T€0 (2R)2 Ri + 4περ R3 - Ri (e)x = 3R: (True,False) 4περ (3R) 2
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