Figure 1(a): SOURCE CODE 1. int T (int x, int y) 2. { 3. int dif = 0; 4. if (odd(x)) 5. x = x/2; 6. else 7. x = x*2; 8. 9. 10. 11. 12. 12. Table 1 // odd (m) is true if and only if x is an odd number << x << endl; << << endl; wwwww Output y = 3*y; dif = x - y cout << "x = " cout << "y = return dif; Invoke Function cout << T (9,2) cout << T (2,9)
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- 14- The following script is used to find the series (g = 1+ e-x+2e-2x + 3e-3x + ..* + 10e-10x) * #include #include using namespace std; int main () {int i; float g=1.0 ,x; cin>>x; for(i=1; i<=10;i++){ s=s+ *exp(-i*x); cout<<"g=l"<need help with this in c++LAB 5.4 Nested LoopsBring in program nested.cpp from the Lab 5 folder (this is Sample Program 5.6from the Pre-lab Reading Assignment). The code is shown below:// This program finds the average time spent programming by a student// each day over a three day period.// PLACE YOUR NAME HERE#include <iostream>using namespace std;int main(){int numStudents;float numHours, total, average;int student,day = 0; // these are the counters for the loopscout << "This program will find the average number of hours a day"<< " that a student spent programming over a long weekend\n\n";cout << "How many students are there ?" << endl << endl;cin >> numStudents;for(student = 1; student <= numStudents; student++){total = 0;for(day = 1; day <= 3; day++){cout << "Please enter the number of hours worked by student "<< student <<" on day " << day << "." << endl;cin >> numHours;continuesLesson 5B 71total = total +…32- The output of the following script is Egg. * #include #include using namespace std; int main() {string myString = "Eng";myString[1] = 'g'; cout << myString;return 0; } true Falseplease answer quicklymain.cpp 1 #include 2 using namespace std; 3 4 int main() 5- { int a,b; cin>>a>>b; int i = a; int total 7 8 9. 0; %3D 10 11 i++; 12 13 cout<1. Find: NINT (7.6) FLOOR (5.75) NINT (-8.66) FLOOR (-6.48) 2. Evaluate the value of the following expression depending on the priority principle. REAL :: A = 2.0 , B = 4.0 , C = -6.0 , R1 R1 = (-B + SQRT (B*B - 4.0*A*C) )/ (2.0*A) 3. If AB = "2638MAHMOOD75" then find: AB(3:8) AB ( :7) AB (5: )1 2 3 4 5 6 7 void main (void) { } 22, с 33, d =44; double a = 11, b double *x [4] = {&a, &b, &c, &d}; double** y = x +1; cout<Zybooks C++ 1.7 LAB: Introduction to data structures labs Step 1: Producing correct output Three commented-out lines of code exist in main(). Uncomment the lines and click the "Run program" button. Verify that the program's output is: 2 + 2 = 4 Unknown function: PrintPlus2 Secret string: "abc" Submit your code for grading. Your submission will pass the "Compare output" test only, achieving 1 of the possible 10 points. Step 2: Inspecting the LabPrinter class Inspect the LabPrinter class implemented in the LabPrinter.h file. Access LabPrinter.h by clicking on the orange arrow next to main.cpp at the top of the coding window. Member functions Print2Plus2() and PrintSecret() print strings using std::cout. Step 3: Implementing CallFunctionNamed() Remove the three uncommented lines from main(). Then implement the CallFunctionNamed() function in main.cpp to handle three cases: If functionName is "Print2Plus2", call printer's Print2Plus2() member function. If functionName is "PrintSecret",…C Programming What does the below code segment do? #define RECORD_LENGTH 60 /* PORTFOLIO.DAT looks like the below: ibm 108.77 27.98 att 111.43 50 acdc 100 30 */ void main(void) { FILE *fptr; char stock_price_shares[RECORD_LENGTH + 1]; int i=0, count=0; // attempt to open PORTFOLIO.DAT for reading if ((fptr = fopen("PORTFOLIO.DAT", "r")) == NULL) printf("\nCannot open the file: PORTFOLIO.DAT\n"); else { while ( fgets(stock_price_shares, RECORD_LENGTH + 1, fptr) != NULL ) printf("\n%s", stock_price_shares); fclose(fptr); //close the file } printf("\nHow many new records for PORTFOLIO.DAT?"); scanf("%d ", &count); fptr = fopen("PORTFOLIO. DAT", "w"); /* writing */ for (i = 0; i < count; ++i) { gets(stock_price_shares); fputs(stock_price_shares, fptr); fclose(fptr); } }C++ prob.task7.c Compare 2 strings function cmp will print out > if s1 is "bigger" than s2, < if s1 is "smaller than s2, = if s1 is "equal" to s2. */ #include <stdio.h> #include <string.h> void cmp(char *s1, char *s2){ return; } int main() { char *string1 = "UNIX rules!"; char *string2 = "Windows drools!"; cmp(string1,string2); return 0; } Start with task7.c, implement the cmp() function. The goal of this function is to compare two strings using the sum of the ASCII value of all the characters in each string. Output of your program should look like this: UNIX rules! is smaller than Windows drools!SEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. 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