Figure 10.12 in your textbook is an energy bar chart for an air-track glider compressing a spring Suppose, instead, a compressed spring launches an air-track glider. Which of the bars of the chart are then greater than zero? Select all that apply. Ki Kf U spi U spf AEth

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**Question:**

Figure 10.12 in your textbook is an energy bar chart for an air-track glider compressing a spring. Suppose, instead, a compressed spring launches an air-track glider. Which of the bars of the chart are then greater than zero?

**Select all that apply:**

- [x] \( K_i \)
- [ ] \( K_f \)
- [ ] \( U_{Sp \, i} \)
- [x] \( U_{Sp \, f} \)
- [ ] \( \Delta E_{th} \)

**Explanation:**

This question asks you to identify which energy components would be greater than zero when a compressed spring is used to launch an air-track glider, based on an energy bar chart scenario.
Transcribed Image Text:**Question:** Figure 10.12 in your textbook is an energy bar chart for an air-track glider compressing a spring. Suppose, instead, a compressed spring launches an air-track glider. Which of the bars of the chart are then greater than zero? **Select all that apply:** - [x] \( K_i \) - [ ] \( K_f \) - [ ] \( U_{Sp \, i} \) - [x] \( U_{Sp \, f} \) - [ ] \( \Delta E_{th} \) **Explanation:** This question asks you to identify which energy components would be greater than zero when a compressed spring is used to launch an air-track glider, based on an energy bar chart scenario.
**Transcription and Explanation of the Image**

### Before:
- **System:**
  - Mass (\(m\)) = 0.50 kg
  - Initial displacement from equilibrium (\(\Delta x_0\)) = 0 m
  - Initial velocity (\(v_0\)): indicated by a green arrow
    
### After:
- Displacement (\(\Delta x_f\)) = 0.027 m
- Final velocity (\(v_f\)) = 0 m/s
- Task: Find \(v_0\)

### Energy Bar Graph:
- Depicts the conservation of mechanical energy
- The left bar represents initial kinetic energy (\(K_i\)) and initial spring potential energy (\(U_{spg_i}\))
- The right bar shows final kinetic energy (\(K_f\)) and final spring potential energy (\(U_{spg_f}\))
- Equation: \(K_i + U_{spg_i} = K_f + U_{spg_f}\)

### Vertical Spring Diagram:
- Includes a box attached to a spring
- Force due to the spring (\(F_{sp}\)) is shown as an upward arrow
- Gravitational force (\(F_G\)) is shown as a downward arrow
- Spring displacement (\(\Delta y\)) = -0.035 m

This content is useful for educational purposes, illustrating the principles of conservation of energy, particularly in systems involving springs and masses.
Transcribed Image Text:**Transcription and Explanation of the Image** ### Before: - **System:** - Mass (\(m\)) = 0.50 kg - Initial displacement from equilibrium (\(\Delta x_0\)) = 0 m - Initial velocity (\(v_0\)): indicated by a green arrow ### After: - Displacement (\(\Delta x_f\)) = 0.027 m - Final velocity (\(v_f\)) = 0 m/s - Task: Find \(v_0\) ### Energy Bar Graph: - Depicts the conservation of mechanical energy - The left bar represents initial kinetic energy (\(K_i\)) and initial spring potential energy (\(U_{spg_i}\)) - The right bar shows final kinetic energy (\(K_f\)) and final spring potential energy (\(U_{spg_f}\)) - Equation: \(K_i + U_{spg_i} = K_f + U_{spg_f}\) ### Vertical Spring Diagram: - Includes a box attached to a spring - Force due to the spring (\(F_{sp}\)) is shown as an upward arrow - Gravitational force (\(F_G\)) is shown as a downward arrow - Spring displacement (\(\Delta y\)) = -0.035 m This content is useful for educational purposes, illustrating the principles of conservation of energy, particularly in systems involving springs and masses.
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