Figure 1 shows the circuit diagram of a square law modulator. The signal applied to nonlinear device, such that a square law can represent it: V2 (t) = 4 V1 (t) + 6 Vr? (t) Vi (t) is the input voltage, and V2(t) is the output voltage. The input voltage is defined by: v1 (1) = 2 COS (2 1 fe t) + 3COS (2 a fm t) Where 2 COS( 2 n fm t) is the message signal and 3 COS( 2a fc t) is the carrier wave. 1. Evaluate the output voltage V2(t) 2. What is the sensitivity of the AM signal
Figure 1 shows the circuit diagram of a square law modulator. The signal applied to nonlinear device, such that a square law can represent it: V2 (t) = 4 V1 (t) + 6 Vr? (t) Vi (t) is the input voltage, and V2(t) is the output voltage. The input voltage is defined by: v1 (1) = 2 COS (2 1 fe t) + 3COS (2 a fm t) Where 2 COS( 2 n fm t) is the message signal and 3 COS( 2a fc t) is the carrier wave. 1. Evaluate the output voltage V2(t) 2. What is the sensitivity of the AM signal
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Transcribed Image Text:Figure 1 shows the circuit diagram of a square law modulator. The signal applied
to nonlinear device, such that a square law can represent it:
V2 (t) = 4 V1 (t) + 6 Vr? (t)
Vi (t) is the input voltage, and V2(t) is the output voltage.
The input voltage is defined by:
v1 (t) = 2 COS (2 t fe t) + 3COS (2 n fm t)
Where 2 COS( 2 n fm t) is the message signal and 3 COS( 2 n fe t) is the carrier
wave.
1. Evaluate the output voltage V2(t)
2. What is the sensitivity of the AM signal
3. What is the power for Vi(t)
4. What is the power of career signal
5. Draw the frequency component for V2(t) (assume fm = 2 KHz, fc = 200 KHz
and the spectrum frequency for the message is impulse)
Nonlinear
device
A. cos (2mf
Tuned to f.
Fig. 1
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