Figure 1 depicts a triaxial cable, commonly applications where high levels of noise rejection are required. The dimensions a, b and c are 3mm, 6mm and 9mm, respectively. The thickness of the cylindrical metal layers is small and may be neglected. The dielectric spacers have the same properties, with E = E2 = 3+ 0.1X. c) used in measurement %3D inner conductor develops potential of 4 = (15 – X) volts and the intermediate conductor is at øâ = -$A- The outer conductor is grounded (c = 0). The a

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X=8
triaxial cable,
in
Figure 1 depicts a
commonly
applications where high levels of noise
rejection are required. The dimensions
a, b and c are 3mm, 6mm and 9mm,
respectively. The thickness of the
cylindrical metal layers is small and
may be neglected. The
spacers have the same properties, with
& = E2 = 3+ 0.1X.
used
measurement
dielectric
The
inner
conductor
develops
a
potential of oA = (15 – X) volts and the
intermediate conductor is at op = -Þa-
The outer conductor is grounded (c =
0).
Figure 1
Sketch a plot of the electric potential as a function of r from the axis
to the outside surface of the cable.
(i)
Note that X is the last digit of your student number. For example,
if your number is C1700123, then ɛ, = ɛ2 = 3 + (0.1)(3) = 3.3 and
PA = (15 – 3) = 12
(ii)
Estiamte the charge densities A on each conductor.
Transcribed Image Text:triaxial cable, in Figure 1 depicts a commonly applications where high levels of noise rejection are required. The dimensions a, b and c are 3mm, 6mm and 9mm, respectively. The thickness of the cylindrical metal layers is small and may be neglected. The spacers have the same properties, with & = E2 = 3+ 0.1X. used measurement dielectric The inner conductor develops a potential of oA = (15 – X) volts and the intermediate conductor is at op = -Þa- The outer conductor is grounded (c = 0). Figure 1 Sketch a plot of the electric potential as a function of r from the axis to the outside surface of the cable. (i) Note that X is the last digit of your student number. For example, if your number is C1700123, then ɛ, = ɛ2 = 3 + (0.1)(3) = 3.3 and PA = (15 – 3) = 12 (ii) Estiamte the charge densities A on each conductor.
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