Fifty nine cities provided information on vacancy rates (in percent) in local apartments in the following frequency distribution. The sample mean and the sample standard deviation are 9% and 3.0%, respectively. (You may find it useful to reference the appropriate table: chi-square table or F table) Vacancy Rate Less than 6 Frequency 12 6 up to 9 9 up to 12 14 20 12 or more 13 a. Apply the goodness-of-fit test for normality at the 5% significance level. Do the sample data suggest that vacancy rates do not follow the normal distribution? First, select the appropriate null and alternative hypotheses. O Ho: Vacancy rates are normally distributed with a mean of 9% and a standard deviation of 3%.; HA: Vacancy rates are not normally distributed with a mean of 9% and a standard deviation of 3%. Ho: Vacancy rates are not normally distributed with a mean of 9% and a standard deviation of 3%.; HA: Vacancy rates are normally distributed with a mean of 9% and a standard deviation of 3%. b. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.) Test statistic

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Fifty nine cities provided information on vacancy rates (in percent) in local apartments in the following frequency distribution. The
sample mean and the sample standard deviation are 9% and 3.0%, respectively. (You may find it useful to reference the appropriate
table: chi-square table or F table)
Vacancy Rate
Less than 6
Frequency
12
6 up to 9
9 up to 12
12 or more
14
20
13
a. Apply the goodness-of-fit test for normality at the 5% significance level. Do the sample data suggest that vacancy rates do not follow
the normal distribution? First, select the appropriate null and alternative hypotheses.
O Ho: Vacancy rates are normally distributed with a mean of 9% and a standard deviation of 3%.; HA: Vacancy rates are not
normally distributed with a mean of 9% and a standard deviation of 3%.
O Ho: Vacancy rates are not normally distributed with a mean of 9% and a standard deviation of 3%.; HA: Vacancy rates are
normally distributed with a mean of 9% and a standard deviation of 3%.
b. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3
decimal places.)
Test statistic
Transcribed Image Text:Fifty nine cities provided information on vacancy rates (in percent) in local apartments in the following frequency distribution. The sample mean and the sample standard deviation are 9% and 3.0%, respectively. (You may find it useful to reference the appropriate table: chi-square table or F table) Vacancy Rate Less than 6 Frequency 12 6 up to 9 9 up to 12 12 or more 14 20 13 a. Apply the goodness-of-fit test for normality at the 5% significance level. Do the sample data suggest that vacancy rates do not follow the normal distribution? First, select the appropriate null and alternative hypotheses. O Ho: Vacancy rates are normally distributed with a mean of 9% and a standard deviation of 3%.; HA: Vacancy rates are not normally distributed with a mean of 9% and a standard deviation of 3%. O Ho: Vacancy rates are not normally distributed with a mean of 9% and a standard deviation of 3%.; HA: Vacancy rates are normally distributed with a mean of 9% and a standard deviation of 3%. b. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.) Test statistic
c. Find the p-value.
0.025 s p-value < 0.05
O 0.01 s p-value < 0.025
Opvalue < 0.01
p-value 2 0.10
O 0.05 s p-value < 0.10
d. What is the conclusion?
O Reject Ho; there is enough evidence to support the claim that the vacancy rates are not normally distributed
O Do not reject Ho; there is enough evidence to support the claim that the vacancy rates are not normally distributed
O Reject Ho; there is not enough evidence to support the claim that the vacancy rates are not normally distributed
Do not reject Ho; there is not enough evidence to support the claim that the vacancy rates are not normally distributed
Transcribed Image Text:c. Find the p-value. 0.025 s p-value < 0.05 O 0.01 s p-value < 0.025 Opvalue < 0.01 p-value 2 0.10 O 0.05 s p-value < 0.10 d. What is the conclusion? O Reject Ho; there is enough evidence to support the claim that the vacancy rates are not normally distributed O Do not reject Ho; there is enough evidence to support the claim that the vacancy rates are not normally distributed O Reject Ho; there is not enough evidence to support the claim that the vacancy rates are not normally distributed Do not reject Ho; there is not enough evidence to support the claim that the vacancy rates are not normally distributed
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