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FGiven the autonomous differential equation y' = (v – 3)²(y – 5) In(y + 4) (a) For which of the initial conditions given below does lim y(t) = -3 (b) What sort of equilibrium is y = 3 for our differential equation? (A) Neither y(2) = 0, y(-4) = - (B) y(2) = 0 (C) Both y(2) = 0, y(-4) = - (D) y(-4) = - 13(a): Select v ↑ Part (a) choices. (A) Semistable (B) Unstable (C) Stable (D) It is not an equilibrium point (E) Cannot be determined 13(b): Select v ↑ Part (b) choices.

FGiven the autonomous differential equation y' = (v – 3)²(y – 5) In(y + 4) (a) For which of the initial conditions given below does lim y(t) = -3 (b) What sort of equilibrium is y = 3 for our differential equation? (A) Neither y(2) = 0, y(-4) = - (B) y(2) = 0 (C) Both y(2) = 0, y(-4) = - (D) y(-4) = - 13(a): Select v ↑ Part (a) choices. (A) Semistable (B) Unstable (C) Stable (D) It is not an equilibrium point (E) Cannot be determined 13(b): Select v ↑ Part (b) choices.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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EGiven the autonomous differential equation У 3 (у — 3) (у - 5) In(y + 4) (a) For which of the initial conditions given below does lim y(t) = -3 (b) What sort of equilibrium is y 3 for our differential equation? 11 (A) Neither y(2) = 0, y(-4) = -4 (B) y(2) = 0 (C) Both y(2) = 0, y(-4) = - (D) y(-4) = (D) У(-4) - || 13(a): Select v ↑ Part (a) choices. (A) Semistable (B) Unstable (C) Stable (D) It is not an equilibrium point (E) Cannot be determined 13(b): Select v ↑ Part (b) choices.
Transcribed Image Text:EGiven the autonomous differential equation У 3 (у — 3) (у - 5) In(y + 4) (a) For which of the initial conditions given below does lim y(t) = -3 (b) What sort of equilibrium is y 3 for our differential equation? 11 (A) Neither y(2) = 0, y(-4) = -4 (B) y(2) = 0 (C) Both y(2) = 0, y(-4) = - (D) y(-4) = (D) У(-4) - || 13(a): Select v ↑ Part (a) choices. (A) Semistable (B) Unstable (C) Stable (D) It is not an equilibrium point (E) Cannot be determined 13(b): Select v ↑ Part (b) choices.
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