Ffrict= From= P=0.50 a= Fnorm (normal force) = Ffrict (force of friction) = Fgrav (force of gravity) = a (acceleration) = ---- ZF (net force) = ____________N O m = 8 kg ΣF= 30° Fgav = 81 7 ______N N ____________N m/s/s, right m/s/s, right Fhens = 60 N W
Ffrict= From= P=0.50 a= Fnorm (normal force) = Ffrict (force of friction) = Fgrav (force of gravity) = a (acceleration) = ---- ZF (net force) = ____________N O m = 8 kg ΣF= 30° Fgav = 81 7 ______N N ____________N m/s/s, right m/s/s, right Fhens = 60 N W
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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g= 10 m/s^2
![### Physics Problem: Force Analysis
#### Problem Description
A block with mass \( m = 8 \) kg is being analyzed for its forces. The block is subject to several forces, including gravitational force, normal force, frictional force, and tension at an angle of \( 30^\circ \). The diagram below illustrates the forces acting on the block:
#### Diagram Explanation
- **Forces Shown:**
- **\( F_{\text{norm}} \)**: Normal force acting perpendicular to the surface.
- **\( F_{\text{tens}} \)**: Tension force acting at an angle of \( 30^\circ \) from the horizontal, with a magnitude of 60 N.
- **\( F_{\text{frict}} \)**: Frictional force opposing the motion.
- **\( F_{\text{grav}} \)**: Gravitational force acting downward.
- **Details:**
- Coefficient of friction (\( \mu \)) is \( 0.50 \).
- The block's mass (\( m \)) is \( 8 \) kg.
#### Calculation Section
Fill in the blanks below with the corresponding forces calculated from the diagram:
1. **Normal Force (\( F_{\text{norm}} \))**:
\[
F_{\text{norm}} = \quad \_\_\_\_\_\_ \text{ N}
\]
2. **Force of Friction (\( F_{\text{frict}} \))**:
\[
F_{\text{frict}} = \quad \_\_\_\_\_\_ \text{ N}
\]
3. **Force of Gravity (\( F_{\text{grav}} \))**:
\[
F_{\text{grav}} = \quad \_\_\_\_\_\_ \text{ N}
\]
4. **Acceleration (\( a \))**:
\[
a = \quad \_\_\_\_\_\_ \text{ m/s}^2 \text{, right}
\]
5. **Net Force (\( \Sigma F \))**:
\[
\Sigma F = \quad \_\_\_\_\_\_ \text{ N}
\]
This exercise helps in understanding the concepts of force balancing, friction, and acceleration in classical mechanics.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F981166fe-4516-4e5d-91f3-95cacb37d8bb%2F10c86ab8-c58c-4aff-b643-0d52a1498666%2F8npdd2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Physics Problem: Force Analysis
#### Problem Description
A block with mass \( m = 8 \) kg is being analyzed for its forces. The block is subject to several forces, including gravitational force, normal force, frictional force, and tension at an angle of \( 30^\circ \). The diagram below illustrates the forces acting on the block:
#### Diagram Explanation
- **Forces Shown:**
- **\( F_{\text{norm}} \)**: Normal force acting perpendicular to the surface.
- **\( F_{\text{tens}} \)**: Tension force acting at an angle of \( 30^\circ \) from the horizontal, with a magnitude of 60 N.
- **\( F_{\text{frict}} \)**: Frictional force opposing the motion.
- **\( F_{\text{grav}} \)**: Gravitational force acting downward.
- **Details:**
- Coefficient of friction (\( \mu \)) is \( 0.50 \).
- The block's mass (\( m \)) is \( 8 \) kg.
#### Calculation Section
Fill in the blanks below with the corresponding forces calculated from the diagram:
1. **Normal Force (\( F_{\text{norm}} \))**:
\[
F_{\text{norm}} = \quad \_\_\_\_\_\_ \text{ N}
\]
2. **Force of Friction (\( F_{\text{frict}} \))**:
\[
F_{\text{frict}} = \quad \_\_\_\_\_\_ \text{ N}
\]
3. **Force of Gravity (\( F_{\text{grav}} \))**:
\[
F_{\text{grav}} = \quad \_\_\_\_\_\_ \text{ N}
\]
4. **Acceleration (\( a \))**:
\[
a = \quad \_\_\_\_\_\_ \text{ m/s}^2 \text{, right}
\]
5. **Net Force (\( \Sigma F \))**:
\[
\Sigma F = \quad \_\_\_\_\_\_ \text{ N}
\]
This exercise helps in understanding the concepts of force balancing, friction, and acceleration in classical mechanics.
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