College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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pls help. acceleration = 4.71m/s^2 and tension = 53.3N but i cant figure it out
![**Problem Statement:**
4. Find the acceleration of the blocks and the tension in the rope.
**Diagram Explanation:**
The diagram illustrates a system with two blocks connected by a rope. The first block has a mass of 8 kg, and the second block has a mass of 4 kg. Both blocks are on a horizontal surface with a coefficient of friction (μ) of 0.2. An external force of 80 N is applied to the 4 kg block horizontally.
**Free Body Diagram Analysis:**
1. **8 kg Block:**
- **Forces:**
- Weight (mg) = 8 kg × 9.8 m/s² = 78.4 N downward
- Normal force (Fn): Upward, equal to the weight
- Frictional Force (Ff): μ × Fn = 0.2 × 78.4 N = 15.68 N, opposing motion
- Tension (T): Acts horizontally towards the 4 kg block
2. **4 kg Block:**
- **Forces:**
- Weight (mg) = 4 kg × 9.8 m/s² = 39.2 N downward
- Normal force (Fn): Upward, equal to the weight
- Frictional Force (Ff): μ × Fn = 0.2 × 39.2 N = 7.84 N, opposing motion
- Tension (T): Acts horizontally towards the 8 kg block
- Applied Force: 80 N acting horizontally
These components are essential for understanding the physics of the system, including calculating the net force, acceleration, and tension.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdcfa255a-8685-4db1-8a78-1a614d4cdb70%2Fa938d40a-f93e-40c8-b592-9963dfc7c043%2F707o77d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
4. Find the acceleration of the blocks and the tension in the rope.
**Diagram Explanation:**
The diagram illustrates a system with two blocks connected by a rope. The first block has a mass of 8 kg, and the second block has a mass of 4 kg. Both blocks are on a horizontal surface with a coefficient of friction (μ) of 0.2. An external force of 80 N is applied to the 4 kg block horizontally.
**Free Body Diagram Analysis:**
1. **8 kg Block:**
- **Forces:**
- Weight (mg) = 8 kg × 9.8 m/s² = 78.4 N downward
- Normal force (Fn): Upward, equal to the weight
- Frictional Force (Ff): μ × Fn = 0.2 × 78.4 N = 15.68 N, opposing motion
- Tension (T): Acts horizontally towards the 4 kg block
2. **4 kg Block:**
- **Forces:**
- Weight (mg) = 4 kg × 9.8 m/s² = 39.2 N downward
- Normal force (Fn): Upward, equal to the weight
- Frictional Force (Ff): μ × Fn = 0.2 × 39.2 N = 7.84 N, opposing motion
- Tension (T): Acts horizontally towards the 8 kg block
- Applied Force: 80 N acting horizontally
These components are essential for understanding the physics of the system, including calculating the net force, acceleration, and tension.
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