### Collision Problem Analysis#### Problem Statement:A 1,135 kg car traveling initially with a speed of 25.0 m/s in an easterly direction crashes into the rear end of a 9,410 kg truck moving in the same direction at 20.0 m/s (see figure below). The velocity of the car right after the collision is 18.0 m/s to the east. The velocity of the truck right after collision is:#### Diagrams:- **Before Collision:** - Car: Rightward (Eastward) at +25.0 m/s - Truck: Rightward (Eastward) at +20.0 m/s- **After Collision:** - Car: Rightward (Eastward) at +18.0 m/s - Truck: **(Velocity to be determined)**#### Multiple Choice Options:A. 25.0 m/s, eastward B. 18.0 m/s, eastward C. 20.8 m/s, eastward D. 25.0 m/s, westward E. 20.8 m/s, westward #### Explanation of Diagrams:The figures provide a visual representation of the motion of the car and truck both before and after the collision. - Before the collision, the car is moving faster (+25.0 m/s) than the truck (+20.0 m/s), indicating it will collide with the rear of the truck.- After the collision, the car slows down to +18.0 m/s, while the truck's speed is to be determined using principles of physics like conservation of momentum. These diagrams help to set the problem for calculating the truck's final velocity. ### Physics Quiz - Forces and Motion#### Question 19:If the box is stationary and the angle θ between the horizontal and force **F** is increased somewhat, what happens to the normal force on the box?![Diagram](image-source.png)- **A.** increases or decreases depending on the value of **F**- **B.** increases- **C.** remains the same- **D.** goes to zero- **E.** decreases#### Question 20:A force acts on a 2.4 kg object in such a way that the position as a function of time is given by \( x = 3.012t - 0.871t^2 + 1.8t^3 \) (x in meters, t in seconds). Find the work done on the object by the force from t = 0 until t = 8.5 seconds.- **A.** 439.765 J- **B.** 631.059 J- **C.** 815.382 J- **D.** 1034.23 J> For more educational resources and practice quizzes, visit our [Educational Website](#).##### Diagram Explanation:The diagram in Question 19 shows a blue box on a horizontal surface. An inclined force **F** is applied to the box at an angle θ with the horizontal axis. This setup helps visualize the effect of changing the angle on the normal force exerted by the surface on the box.

Answered: Image /qna-images/answer/fce65528-a0fc-422d-a5a8-86820db9a880.jpg

FEED UESTION 19 If the box is stationary and the angle between the horizontal and force F is increased somewhat, what happens to the normal force on the box? A. increases or decreases depending on the value of F OB. increases OC. remains the same O D. goes to zero O E. decreases QUESTION 20 MacBook Air 1052 J KOD WAZ 20 myUBCARD de 5 308088A A force acts on a 2.1 kg object in such a way that the position as a function of time is given by x=0.92t-0.87t+1.8t (x is in meters; t is in seconds). Find the work done on the object by the force from t = 0 and t = 8.9 s. A. 438765 J 9888

FEED UESTION 19 If the box is stationary and the angle between the horizontal and force F is increased somewhat, what happens to the normal force on the box? A. increases or decreases depending on the value of F OB. increases OC. remains the same O D. goes to zero O E. decreases QUESTION 20 MacBook Air 1052 J KOD WAZ 20 myUBCARD de 5 308088A A force acts on a 2.1 kg object in such a way that the position as a function of time is given by x=0.92t-0.87t+1.8t (x is in meters; t is in seconds). Find the work done on the object by the force from t = 0 and t = 8.9 s. A. 438765 J 9888

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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