Based on information from the Federal Highway Administration web site, the average annual miles driven per vehicle in the United States is 13.5 thousand miles. Assume σ ≈ 650 miles. Suppose that a random sample of 41 vehicles owned by residents of Chicago showed that the average mileage driven last year was 13.2 thousand miles. Would this indicate that the average miles driven per vehicle in Chicago is different from (higher or lower than) the national average? Use a 0.05 level of significance. What are we testing in this problem?single meansingle proportion (a) What is the level of significance? State the null and alternate hypotheses.H0: p = 13.5; H1: p < 13.5H0: p = 13.5; H1: p ≠ 13.5 H0: μ = 13.5; H1: μ < 13.5H0: μ = 13.5; H1: μ > 13.5H0: p = 13.5; H1: p > 13.5H0: μ = 13.5; H1: μ ≠ 13.5(b) What sampling distribution will you use? What assumptions are you making?The Student's t, since we assume that x has a normal distribution with unknown σ.The standard normal, since we assume that x has a normal distribution with unknown σ. The standard normal, since we assume that x has a normal distribution with known σ.The Student's t, since we assume that x has a normal distribution with known σ.What is the value of the sample test statistic? (Round your answer to two decimal places.) (c) Find (or estimate) the P-value. P-value > 0.5000.250 < P-value < 0.5000.100 < P-value < 0.2500.050 < P-value < 0.1000.010 < P-value < 0.050P-value < 0.010

Name: Based on information from the Federal Highway Administration web site,
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Description: Based on information from the Federal Highway Administration web site, the average annual miles driven per vehicle in the United States is 13.5 thousand miles. Assume σ ≈ 650 miles. Suppose that a random sample of 41 vehicles owned by residents of Ch

The objective is to test whether that the average miles driven per vehicle in Chicago is different…

Answered: Federal Highway Administration web…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

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Based on information from the Federal Highway Administration web site, the average annual miles driven per vehicle in the United States is 13.5 thousand miles. Assume σ ≈ 650 miles. Suppose that a random sample of 41 vehicles owned by residents of Chicago showed that the average mileage driven last year was 13.2 thousand miles. Would this indicate that the average miles driven per vehicle in Chicago is different from (higher or lower than) the national average? Use a 0.05 level of significance.

What are we testing in this problem?

single meansingle proportion

(a) What is the level of significance?

State the null and alternate hypotheses.

H₀: p = 13.5; H₁: p < 13.5H₀: p = 13.5; H₁: p ≠ 13.5 H₀: μ = 13.5; H₁: μ < 13.5H₀: μ = 13.5; H₁: μ > 13.5H₀: p = 13.5; H₁: p > 13.5H₀: μ = 13.5; H₁: μ ≠ 13.5

(b) What sampling distribution will you use? What assumptions are you making?

The Student's t, since we assume that x has a normal distribution with unknown σ.

The standard normal, since we assume that x has a normal distribution with unknown σ.

The standard normal, since we assume that x has a normal distribution with known σ.

The Student's t, since we assume that x has a normal distribution with known σ.

What is the value of the sample test statistic? (Round your answer to two decimal places.)

(c) Find (or estimate) the P-value.

P-value > 0.5000.

250 < P-value < 0.500

0.100 < P-value < 0.250

0.050 < P-value < 0.100

0.010 < P-value < 0.050

P-value < 0.010

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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