Fe3+ + 1e → Fe²+ Pb2+ + 2e E° = 0.77 V Pb Eº= -0.13 V

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Question

When the two half cells are combined under standard conditions to form a voltaic cell, which will be the oxidation half-reaction?

a) Pb2+ + 2e- → Pb
b) Pb → Pb2+ + 2e-
c) Fe3+ + 3e- → Fe2+
d) Fe2+ → Fe3+ + 3e-
e) Not sure

 
 
Fe3+ + 1e → Fe²+
Pb2+ + 2e
E° = 0.77 V
Pb
Eº= -0.13 V
Transcribed Image Text:Fe3+ + 1e → Fe²+ Pb2+ + 2e E° = 0.77 V Pb Eº= -0.13 V
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