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■fcc structure is

■fcc structure is

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2. Nearest neighbour distance. (a) Show that the distance between two nearest neighbouring atoms in an fee structure is a/V2, a being the edge of conventional cubic unit cell. (b) Diamond lattice is a combination of two interpenetrating fcc lat- tices displaced relative to each other along the body diagonal by a/4. Obtain the nearest neighbour distance for the structure in terms of a. (c) Si crystallizes in dia- mond structure with a = 5.430 Å. Calculate nearest neighbour distance for it
Transcribed Image Text:2. Nearest neighbour distance. (a) Show that the distance between two nearest neighbouring atoms in an fee structure is a/V2, a being the edge of conventional cubic unit cell. (b) Diamond lattice is a combination of two interpenetrating fcc lat- tices displaced relative to each other along the body diagonal by a/4. Obtain the nearest neighbour distance for the structure in terms of a. (c) Si crystallizes in dia- mond structure with a = 5.430 Å. Calculate nearest neighbour distance for it
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