Fatima is saving up to buy a $300 bike. She saves $25 each week from her babysitting money. Which linear equation represents the amount Fatima still has to save after x weeks? O A. y= 25x + 300 о в. у3 25х - 300 о с. у3-25х - 300 O D. y = -25x + 300
Fatima is saving up to buy a $300 bike. She saves $25 each week from her babysitting money. Which linear equation represents the amount Fatima still has to save after x weeks? O A. y= 25x + 300 о в. у3 25х - 300 о с. у3-25х - 300 O D. y = -25x + 300
Algebra and Trigonometry (6th Edition)
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Fatima is saving up to buy a $300 bike. She saves $25 each week from her babysitting money. Which linear equation represents the amount Fatima still has to save after x weeks?
![**Problem Statement:**
Fatima is saving up to buy a $300 bike. She saves $25 each week from her babysitting money. Which linear equation represents the amount Fatima still has to save after \( x \) weeks?
**Options:**
- A. \( y = 25x + 300 \)
- B. \( y = 25x - 300 \)
- C. \( y = -25x - 300 \)
- D. \( y = -25x + 300 \)
**Explanation:**
To solve this problem, we need to determine how much money Fatima still needs to save after \( x \) weeks. The initial amount she needs is $300. Each week, she saves $25, reducing the amount she needs to save.
The correct linear equation should decrease by $25 per week. Therefore, it should be a subtraction from the initial amount of $300.
The equation should take the form:
\[ y = 300 - 25x \]
This is equivalent to option D:
\[ y = -25x + 300 \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe96db4eb-3ebc-4fc6-803f-a7c6c6df15aa%2F31f47f88-f41a-436c-a43c-d5fcc4f96b23%2Fz6tl2i_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Fatima is saving up to buy a $300 bike. She saves $25 each week from her babysitting money. Which linear equation represents the amount Fatima still has to save after \( x \) weeks?
**Options:**
- A. \( y = 25x + 300 \)
- B. \( y = 25x - 300 \)
- C. \( y = -25x - 300 \)
- D. \( y = -25x + 300 \)
**Explanation:**
To solve this problem, we need to determine how much money Fatima still needs to save after \( x \) weeks. The initial amount she needs is $300. Each week, she saves $25, reducing the amount she needs to save.
The correct linear equation should decrease by $25 per week. Therefore, it should be a subtraction from the initial amount of $300.
The equation should take the form:
\[ y = 300 - 25x \]
This is equivalent to option D:
\[ y = -25x + 300 \]
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