fardware & Architecture HW #7-100 Pts f= DCBA DEBA + PC BA + DC BA+ 2. (10 Pts) Derive an Un-simplified SOP Boolean expression for the Binary output DC BA+ + DCBA DCBA 3. (10 Pts) Simplify the SOP Boolean expression for the Binary output using a Karnaugh Map CP 9/0/0/01 0 1 L 10 SOP CD+ BBFABC Grouping COD=1 BD=W ABC=W 4. (20 Pts) Draw the logic circuit for the simplified Boolean expression for the Binary output. A ABC BD CD F= CB+BD+ ABC 5. (20 Pts) Implement the design using a 4 to 16 Decoder and logic gates, combining the "Yes" combinations into a single output and the "Maybe" combinations into another output 6. (20 Pts) Implement the design using a 1 to 16 Multiplexer. Only the "Yes" output needs to be represented by this implementation.
fardware & Architecture HW #7-100 Pts f= DCBA DEBA + PC BA + DC BA+ 2. (10 Pts) Derive an Un-simplified SOP Boolean expression for the Binary output DC BA+ + DCBA DCBA 3. (10 Pts) Simplify the SOP Boolean expression for the Binary output using a Karnaugh Map CP 9/0/0/01 0 1 L 10 SOP CD+ BBFABC Grouping COD=1 BD=W ABC=W 4. (20 Pts) Draw the logic circuit for the simplified Boolean expression for the Binary output. A ABC BD CD F= CB+BD+ ABC 5. (20 Pts) Implement the design using a 4 to 16 Decoder and logic gates, combining the "Yes" combinations into a single output and the "Maybe" combinations into another output 6. (20 Pts) Implement the design using a 1 to 16 Multiplexer. Only the "Yes" output needs to be represented by this implementation.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
help me with question 5 and 6 and this is not a quiz it is homework

Transcribed Image Text:fardware & Architecture HW #7-100 Pts
f= DCBA DEBA + PC BA + DC BA+
2. (10 Pts) Derive an Un-simplified SOP Boolean expression for the Binary output DC BA+
+ DCBA DCBA
3. (10 Pts) Simplify the SOP Boolean expression for the Binary output using a Karnaugh Map
CP
9/0/0/01
0
1 L
10
SOP
CD+ BBFABC
Grouping
COD=1
BD=W
ABC=W
4. (20 Pts) Draw the logic circuit for the simplified Boolean expression for the Binary output.
A
ABC
BD
CD
F= CB+BD+ ABC
5. (20 Pts) Implement the design using a 4 to 16 Decoder and logic gates, combining the "Yes"
combinations into a single output and the "Maybe" combinations into another output
6. (20 Pts) Implement the design using a 1 to 16 Multiplexer. Only the "Yes" output needs
to be represented by this implementation.
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