False Position Method Function is given Iteration 0 1 2 3 4 5 6 f(n) = 40n¹-5-875n+ 35000 = 0 a f(a) b f(b) с f(c) f(a) f(c) f(b) f(c) error=abs(ci+1-ci) PLEASE PROVIDE THE FORMULA ON SOLVING THIS NON-LINEAR EQUATION BY THE GIVEN METHOD

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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A
False Position Method
Function is given
Iteration
0
1
2
3
4
5
6
B
с
f(n) = 40n¹.5 - 875n+ 35000 = 0
a
f(a)
D
b
E
f(b)
F
с
G
f(c)
H
f(a) *f(c)
I
f(b) *f(c)
J
error=abs(ci+1-ci)
PLEASE PROVIDE THE FORMULA ON SOLVING THIS NON-LINEAR EQUATION BY THE
GIVEN METHOD
K
Transcribed Image Text:1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 A False Position Method Function is given Iteration 0 1 2 3 4 5 6 B с f(n) = 40n¹.5 - 875n+ 35000 = 0 a f(a) D b E f(b) F с G f(c) H f(a) *f(c) I f(b) *f(c) J error=abs(ci+1-ci) PLEASE PROVIDE THE FORMULA ON SOLVING THIS NON-LINEAR EQUATION BY THE GIVEN METHOD K
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