Factor: 10k + 10m – 2km - 2m2 Since all four terms have a common factor of 2, we factor it out first. Then we will factor the resulting polynomial by grouping. Factoring out the GCF first makes factoring by any method easier. After factoring out 2 from all four terms, notice that within the parentheses, the first two terms have a common factor of 5, and the last two terms have a common factor of -m. 10k + 10m – 2km – 2m2 = (5k + 5m – km – m²) Factor out the GCF, 2. = 2[ (k + m) – m(k + m)) Factor out 5 from 5k + 5m. Factor out -m from -km – m². This causes the signs of -km and –m² to change within the second set of parentheses. = 2[(k + m)( - m)] |(k + m)(5 – m) Factor out the common binomial factor, k + m. Drop the unnecessary brackets. Check by multiplying. Factor: 4t + 4s + 4tz + 4sz
Factor: 10k + 10m – 2km - 2m2 Since all four terms have a common factor of 2, we factor it out first. Then we will factor the resulting polynomial by grouping. Factoring out the GCF first makes factoring by any method easier. After factoring out 2 from all four terms, notice that within the parentheses, the first two terms have a common factor of 5, and the last two terms have a common factor of -m. 10k + 10m – 2km – 2m2 = (5k + 5m – km – m²) Factor out the GCF, 2. = 2[ (k + m) – m(k + m)) Factor out 5 from 5k + 5m. Factor out -m from -km – m². This causes the signs of -km and –m² to change within the second set of parentheses. = 2[(k + m)( - m)] |(k + m)(5 – m) Factor out the common binomial factor, k + m. Drop the unnecessary brackets. Check by multiplying. Factor: 4t + 4s + 4tz + 4sz
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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I need help with all of them plz.
![Factor: 10k + 10m
2km
2m2
Since all four terms have a common factor of 2, we factor it out first. Then we will factor the resulting polynomial by grouping.
Factoring out the GCF first makes factoring by any method easier.
After factoring out 2 from all four terms, notice that within the parentheses, the first two terms have a common factor of 5, and the last two terms have a common
factor of -m.
10k + 10m
2km – 2m2
(5k + 5m – km
m²)
Factor out the GCF, 2.
2[
(k + m) – m(k + m)] Factor out 5 from 5k + 5m. Factor out –m from -km – m². This causes the signs of –km and –m²
to change within the second set of parentheses.
2[(k + m)(
m)]
Factor out the common binomial factor, k + m.
%3D
(k + m)(5 – m)
Drop the unnecessary brackets.
Check by multiplying.
Factor: 4t + 4s + 4tz + 4sz](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9a233757-ff48-478f-9071-7d7d23b994ff%2F1bae8a9e-9f22-426c-ada8-69aeb350ee7c%2Fyj0163q_processed.png&w=3840&q=75)
Transcribed Image Text:Factor: 10k + 10m
2km
2m2
Since all four terms have a common factor of 2, we factor it out first. Then we will factor the resulting polynomial by grouping.
Factoring out the GCF first makes factoring by any method easier.
After factoring out 2 from all four terms, notice that within the parentheses, the first two terms have a common factor of 5, and the last two terms have a common
factor of -m.
10k + 10m
2km – 2m2
(5k + 5m – km
m²)
Factor out the GCF, 2.
2[
(k + m) – m(k + m)] Factor out 5 from 5k + 5m. Factor out –m from -km – m². This causes the signs of –km and –m²
to change within the second set of parentheses.
2[(k + m)(
m)]
Factor out the common binomial factor, k + m.
%3D
(k + m)(5 – m)
Drop the unnecessary brackets.
Check by multiplying.
Factor: 4t + 4s + 4tz + 4sz
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